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3 years ago

If sin x = .21, what is cos x

Mathematics

1 answer:

nika2105 [10]3 years ago

6 0

0.999993283193413 is the answer. You may have to round.

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Which number line shows the solution to the inequality -3x - 5 < -2 ?

Inessa05 [86]

The answer to his is A

3 0

3 years ago

SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS

antiseptic1488 [7]

Answer:

$\sf -11+7\sqrt{2}$

Step-by-step explanation:

Given expression:

$\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }$

Rewrite 32 as 16 · 2:

$\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }$

Apply radical rule $\sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }$

As $\sf \sqrt{16}=4$ :

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }$

Multiply by the conjugate:

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }$

$\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}$

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}$

As $\sf \sqrt{2}\sqrt{2}=\sqrt{4}=2$ :

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}$

$\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}$

$\sf \implies \dfrac{11-7\sqrt{2}}{-1}$

$\sf \implies -11+7\sqrt{2}$

7 0

2 years ago

PLEASE HELP ILL GIVE MEDALS AND MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!! NEEDS TO BE ALEGABRA 2 MEATHOD!!!!!!!!

nevsk [136]

Simplify \frac{5}{3}x35x to \frac{5x}{3}35x

x-\frac{5x}{3}<3x−35x<3

2

Simplify x-\frac{5x}{3}x−35x to -\frac{2x}{3}−32x

-\frac{2x}{3}<3−32x<3

3

Multiply both sides by 33

-2x<3\times 3−2x<3×3

4

Simplify 3\times 33×3 to 99

-2x<9−2x<9

5

Divide both sides by -2−2

x>-\frac{9}{2}x>−29

8 0

3 years ago

Solve for x<br><br> 0.25x=10

Ad libitum [116K]

X=40 hope this helps nig

7 0

3 years ago

Read 2 more answers

zalisa [80]

1.) y-7=4(x+3)
2.) y+7=(x-1)
3.) y-3=6(x+8)

6 0

2 years ago