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2 years ago

The triangle below is isosceles.

Mathematics

1 answer:

nlexa [21]2 years ago

3 0

Answer:

BC = 20 units

Step-by-step explanation:

if ∡C = ∡B then 2x + 16 = 7x + 6

16 = 5x + 6

10 = 5x

x = 2

BC = 2(2) + 16, which is 20

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Solve the given inequality. Round to the nearest ten-thousandth, if necessary. e x > 14

Bess [88]

Answer:

$x\in(1.146,\infty)$

Step-by-step explanation:

We are given an inequality

$e^x>14$

We have to solve the given inequality.

Taking both side ln of given inequality

Then, we get

$ln(e^x)>ln(14)$

$xlne>1.146$

We know that

lne=1

Using the value

$x>1.146$

$x\in(1.146,\infty)$

Hence, the value of x is given by

$x\in(1.146,\infty)$

8 0

3 years ago

Help, please. This is related to mirror and shadow problems

nadya68 [22]

Answer:

1. x/2=1.75/3.5 x=1

2. 4/2=y/3.5 y=3.5

3. P (Figure Left)=3+5+2+1+4+8+3+2=28 cm

A (Figure Left)=8x2-2x1-3x2=8 cm2

4. P (Figure Left) / P (Figure Right) = 1/1.75 = 28/ P (Figure Right)

P (Figure Right)= 49 cm

A (Figure Left) / A (Figure Right) = 1/1.752 = 8/ A (Figure Right)

A(Figure Right)= 24.5 cm2

Step-by-step explanation:

1. x/2=1.75/3.5 x=1

2. 4/2=y/3.5 y=3.5

3. P (Figure Left)=3+5+2+1+4+8+3+2=28 cm

A (Figure Left)=8x2-2x1-3x2=8 cm2

4. P (Figure Left) / P (Figure Right) = 1/1.75 = 28/ P (Figure Right)

P (Figure Right)= 49 cm

A (Figure Left) / A (Figure Right) = 1/1.752 = 8/ A (Figure Right)

A(Figure Right)= 24.5 cm2

5 0

2 years ago

Phil has 5 times as many toy race cars as Richard has. Phil has 425 toy race cars. How many race cars does Richard have? *

Wewaii [24]

Answer:

Step-by-step explanation:

425 divided by 8= 85

4 0

2 years ago

Read 2 more answers

3 over 8 plus 2 over 3 plus 1 over 3

wariber [46]

3 over 8 plus 2 over 3 plus 1 over 3 = 11 over 8 or 1.375

4 0

3 years ago

Read 2 more answers

GREYUIT [131]

Answer:

$175\ in^{2}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> volume of the larger solid

y----> volume of the smaller solid

$z^{3}=\frac{x}{y}$

we have

$x=125\ in^{3}$

$y=27\ in^{3}$

substitute

$z^{3}=\frac{125}{27}$

$z=\frac{5}{3}$

step 2

Find the surface area of the larger solid

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the larger solid

y----> surface area of the smaller solid

$z^{2}=\frac{x}{y}$

we have

$z=\frac{5}{3}$

$y=63\ in^{2}$

substitute

$(\frac{5}{3})^{2}=\frac{x}{63}$

$x=\frac{25}{9}*63=175\ in^{2}$

3 0

3 years ago