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ELEN [110]
3 years ago
10

Can someone help me?​

Mathematics
2 answers:
Kipish [7]3 years ago
8 0
The answer is 3 for sure.
andreev551 [17]3 years ago
6 0

Answer:

3. p ≥ 15

Step-by-step explanation:

When there is an "at least" we can say that the sign relating p and 15 has to have an underline since p can be equal to 15. And, also, it implies that p is greater. When we put this together, we get:

p ≥ 15

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Help please 10points
ikadub [295]

Answer:

Have you tried copying and pasting?

Step-by-step explanation:

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6 0
3 years ago
Use the diagram and given information to answer the questions and prove the statement.
Greeley [361]

Answer:

See explanation

Step-by-step explanation:

<u> ASA Postulate (Angle-Side-Angle):</u>

If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

Consider triangles XYB and ZYA. In these triangles

  • ∠X≅∠Z (given)
  • XY≅ZY (given)
  • ∠Y is common angle

By ASA Postulate, triangles XYB and ZYA are congruent. Congruent triangles have congruent corresponding sides, so

BX≅AZ

6 0
3 years ago
Which had the greater absolute value <br> 19 or -28
nignag [31]

Answer:

-28 has the greater absolute value.

Step-by-step explanation:

19's absolute value is 19

|19|=19

but -28's absolute value is 28

|-28|=28

and 28 is greater than 19

19<28

hope u understood and it helps

if any doubt, don't hesitate to ask in the comments

and ur welcm

:)

8 0
3 years ago
Write in simplest radical form: √208
Arte-miy333 [17]

208:2=104\\104:2=52\\52:2=26\\26:2=13\\13:13=1\\\\208=2\cdot2\cdot2\cdot2\cdot13=2^2\cdot2^2\cdot13\\\\\sqrt{208}=\sqrt{2^2\cdot2^2\cdot13}=\sqrt{2^2}\cdot\sqrt{2^2}\cdot\sqrt{13}=2\cdot2\cdot\sqrt{13}=4\sqrt{13}\\\\Answer:\ \sqrt{208}=4\sqrt{13}\\\\Used:\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a

6 0
4 years ago
The diameter of a circle is 14 m. Find its area in terms of \piπ.
Lena [83]
43.96 is what i got! im sorry if i got it wrong
6 0
3 years ago
Read 2 more answers
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