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3 years ago

Do clouds need high or low pressure to form?

Physics

2 answers:

Andrej [43]3 years ago

7 0

Explanation:

I think A low-pressure system draws air in. Any air present is pushed upwards by it.

gtnhenbr [62]3 years ago

4 0

Low pressure. hope this helps :)

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What would be the projectile's initial speed?

zalisa [80]

Math is the process of using the given information, along with
all the general stuff that you know, to find the missing information.
With no given information, we have no way to even guess at
an answer.

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4 years ago

A circuit consists of a resistance R, and an inductance L in parallel connected, which is in series with a second resistance R2.

Allisa [31]

Answer:

The impedance of the inductor is ω L:

This is in parallel wth R giving a resistance of the parallel combination:

1 / Rp = 1 / ω L + 1 / R

Rp = (ω L * R) / (ω L + R) for the impedance of the parallel combination

Total resistance (impedance) Rt = Rp + R2 = Z

One can use the term impedance to show that the resulting current is not in phase with the resulting voltage

phase angle φ - cos φ = ω L / Rt

V = I Z shows the relation of voltage and urrent

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2 years ago

Is it true that mproving overall fitness may not be possible for people who have physical limitations.

OleMash [197]

That's not true people that have a broken leg use crutches and the constant lifting of their own body weight will help them gain muscle

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4 years ago

A body is traveling at 5.0 m/s along the positive direction of an x axis; no net force acts on the body. An internal explosion s

loris [4]

To solve this problem it is necessary to apply the concepts related to the conservation of momentum and conservation of kinetic energy.

By definition kinetic energy is defined as

$KE = \frac{1}{2} mv^2$

Where,

m = Mass

v = Velocity

On the other hand we have the conservation of the moment, which for this case would be defined as

$m*V_i = m_1V_1+m_2V_2$

Here,

m = Total mass (8Kg at this case)

$m_1=m_2 =$ Mass each part

$V_i =$ Initial velocity

$V_2 =$ Final velocity particle 2

$V_1 =$ Final velocity particle 1

The initial kinetic energy would be given by,

$KE_i=\frac{1}{2}mv^2$

$KE_i = \frac{1}{2}8*5^2$

$KE_i = 100J$

In the end the energy increased 100J, that is,

$KE_f = KE_i KE_{increased}$

$KE_f = 100+100 = 200J$

By conservation of the moment then,

$m*V_i = m_1V_1+m_2V_2$

Replacing we have,

$(8)*5 = 4*V_1+4*V_2$

$40 = 4(V_1+V_2)$

$V_1+V_2 = 10$

$V_2 = 10-V_1$ (1)

In the final point the cinematic energy of EACH particle would be given by

$KE_f = \frac{1}{2}mv^2$

$KE_f = \frac{1}{2}4*(V_1^2+V_2^2)$

$200J=\frac{1}{2}4*(V_1^2+V_2^2)$ (2)

So we have a system of 2x2 equations

$V_2 = 10-V_1$

$200J=\frac{1}{2}4*(V_1^2+V_2^2)$

Replacing (1) in (2) and solving we have to,

200J=\frac{1}{2}4*(V_1^2+(10-V_1)^2)

PART A: $V_1 = 10m/s$

Then replacing in (1) we have that

PART B: $V_2 = 0m/s$

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3 years ago

In a circult, a battery is used to

Fudgin [204]

Answer:

4. convert electrical energy into some other form of energy

7 0

3 years ago

Read 2 more answers