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beks73 [17]
4 years ago
5

To combine integers with different signs find their _ _ then _ the smaller absolute value from the larger one give the sum the s

ign of the number with the _ absolute
Mathematics
1 answer:
liubo4ka [24]4 years ago
5 0

Answer:

  • absolute values
  • subtract
  • largest

Step-by-step explanation:

To combine integers with different signs find their <u>absolute values</u> then <u>subtract</u> the smaller absolute value from the larger one. Give the sum the sign of the number with the <u>largest</u> absolute value.

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What is the correct answer? please only put the answer.
KatRina [158]

Answer:

156

Step-by-step explanation:

5 0
3 years ago
**A rock dropped from a 100 foot tower.
mars1129 [50]

Answer:

2.83 s

Step-by-step explanation:

We are given that

h(t)=-16t^2+10t+100

When a rock reached the ground then h(t)=0

-16t^2+10t+100=0

16t^2-10t-100=0

Using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

t=\frac{10\pm\sqrt{(-10)^2-4\times 16\times (-100)}}{2(16)}

t=\frac{10\pm\sqrt{100+6400}}{32}

t=\frac{10+\sqrt{6500}}{32}=2.83

t=\frac{10-\sqrt{6500}}{32}=-2.2

Time cannot be negative .Therefore, negative value of t can not be possible.

Hence, the rock takes 2.83 sec to reach the ground.

8 0
4 years ago
Use the distributive property to solve the equation 28 - (3x + 4) = 2(x + 6) + 5
Shalnov [3]
1.) 28-3x-4= 2x+12+x
2.) 24-3x= 3x+12
3.)24-6x=12
4.)-6x=-12
5.)x=2
7 0
3 years ago
Sheena was organizing items in a scrapbook she took 25 photos and divided them evenly between p pages which algebraic expression
erma4kov [3.2K]
P divided by 25 that depends on how many pages there are on her scrapbook
5 0
3 years ago
Read 2 more answers
Power (denoted by PPP) can be defined as a function of work (denoted by WWW) and time (denoted by ttt) using this formula: P=\df
Amanda [17]

Answer:

\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}

Step-by-step explanation:

Power (denoted by P) can be defined as a function of work (denoted by W) and time (denoted by t) using this formula:

P=\dfrac{W}{t}

Unit of Work = \dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2}

Unit for Time = s

Therefore, the Unit of Power

=$Unit for W \times \dfrac{1}{\text{Unit for time}}

=\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^2} \times \dfrac{1}{s} \\=\dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}

An appropriate unit for power is: \dfrac{\text{kg}\cdot\text{m}^2}{\text{s}^3}

3 0
3 years ago
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