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2 years ago

Why is a rise in sea level significant?

Chemistry

2 answers:

pogonyaev2 years ago

8 0

Answer:

I honestly dont know but its cool problably from water fill or from the waves going to much

Explanation:

VLD [36.1K]2 years ago

5 0

The answer I can think of is it might be the way the water has waves and it moves a lot

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N2(g) + 3H2(g) → 2NH3(g) How many grams of N2 are required to produce 240.0g NH3?

just olya [345]

Answer:

$\large \boxed{\text{197.4 g}}$

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 28.01 17.03

N₂ + 3H₂ ⟶ 2NH₃

m/g: 240.0

(a) Moles of NH₃

$\text{Moles of NH}_{3} = \text{240.0 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.09 mol NH}_{3}$

(b) Moles of N₂

$\text{Moles of N$_{2}$} = \text{14.09 mol NH}_{3} \times \dfrac{\text{1 mol N$_{2}$}}{\text{2 mol NH}_{3}} = \text{7.046 mol N$_{2}$}$

(c) Mass of N₂

$\text{Mass of N$_{2}$} =\text{7.046 mol N$_{2}$} \times \dfrac{\text{28.01 g N$_{2}$}}{\text{1 mol N$_{2}$}} = \textbf{197.4 g N$_{2}$}\\\\\text{The reaction requires $\large \boxed{\textbf{197.4 g}}$ of N$_{2}$}$

7 0

3 years ago

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If an automobile air bag has a volume of 11.5 l , what mass of nan3 (in

True [87]

Moles of NaN3 at STP = volume of gas / 22.4 = 11.5/22.4 = 0.5mole. Massof NaN3 = moles of NaN3 x molecular weight = 0.5 x 65 = 32.5 grams.

8 0

3 years ago

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1 Calcium carbonate breaks down on heating to produce calcium oxide and carbon dioxide gas.

Alborosie

Answer: See below

Explanation:

1. a) 0.15 moles calcium carbonate (15g/100g/mole)

b) 0.15 moles CaO (molar ratio of CaO to CaCO3 is 1:1)

c) 8.4 grams CaO (0.15 moles)*(56 grams/mole)

2. a) 0.274 moles Na2O (17g/62 grams/mole)

b) 46.6 grams NaNO3 (2 moles NaNO3/1 mole Na2O)*(0.274 moles Na2O)*(85 g/mole NaNO3)

7 0

3 years ago

Abhfguojgedfhoobdssghjbhjjbjkjjk<br><br><br> friends ?

Sholpan [36]

Answer:

yessss what's ur snapp?

6 0

3 years ago

A certain liquid has a vapor pressure of 92.0 Torr at 23.0 °C and 351.0 Torr at 45.0 °C. Calculate the value of ΔH°vap for this

notka56 [123]

There is a specific formula to use for these type of problems.

ln (P2/ P1)= Δvap/ R x (1/T1 - 1/T2)

R= 8.314
P1= 92.0 torr
T1= 23 C + 273= 296 K
P2= 351.0 torr
T2= 45.0 C + 273= 318 K

plug the values and solve for the unknown

ln( 351.0/ 92.0)= Δvap/ 8.314 x (1/296 - 1/318)

Δvap= 47630.6 joules

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3 years ago

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