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igomit [66]
3 years ago
14

Which of the following is a change of state?

Chemistry
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

I think C. Hope this Helps!

Explanation:

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What happened to a liquid when it releases enough energy
malfutka [58]
The liquid will freeze

7 0
3 years ago
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Estimate the percent ionic character of the co bond. (note that the electronegativity of c is 2.5 and that of o is 3.5.)
deff fn [24]

From the calcuation, the percent ionic character of the bond is  70%

<h3>What is percent ionic character?</h3>

The term percent ionic character has to do with the degree of ionic bonding that is contained in a compound. It can be estimated from the electronegativity of each element.

We can use the formula; 100(1 - e^(-ΔEN² / 4))

EN = χB − χA * 100/1

EN = 3.5 - 1.5 = 1

100(1 - e^(-1)^2/4)

= 70%

Learn more about percent ionic character:brainly.com/question/7034446

#SPJ1

5 0
2 years ago
PLEASE HELP ASAP!
Airida [17]

Answer:

Direct relationship

Explanation:

I took the test. Good luck!

7 0
3 years ago
Read 2 more answers
For the reaction Na + H2O → NaOH + H2, what are the reactants, products, and correct coefficients in the balanced equation? Reac
horrorfan [7]

The correct answer is reactants 2Na and 2H₂O and products 2NaOH and 1H₂.  

The given unbalanced chemical equation is:  

Na (s) + H2O (l) → NaOH (aq) + H₂ (g)

From the equation, it can be seen that there are three atoms of hydrogen on the products side, however, only two on the reactant's side. So, in order to balance the equation, one needs to multiply the sodium hydroxide by 2 to get a total of 4 atoms of hydrogen on the product's side.  

This will enable one to readily double the number of molecules of water to get 4 atoms of hydrogen on the reactants side, and then balance the atoms of sodium by multiplying the sodium metal by 2. The balanced equation obtained is:  

2Na (s) + 2H₂O (l) → 2NaOH (aq) + H₂ (g)


7 0
3 years ago
Read 2 more answers
The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C
Kay [80]

<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

  • <u>For _{17}^{35}\textrm{Cl} isotope:</u>

Mass of _{17}^{35}\textrm{Cl} isotope = 35 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

  • <u>For _{17}^{37}\textrm{Cl} isotope:</u>

Mass of _{17}^{37}\textrm{Cl} isotope = 37 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775

Percentage abundance of _{17}^{35}\textrm{Cl} isotope = 0.775\times 100=77.5\%

Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.775)=0.225\times 100=22.5\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

6 0
3 years ago
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