<u>Answer:</u> The temperature increase will be 31.70°C.
<u>Explanation:</u>
To calculate the increase in the temperature of the system, we use the equation:

where,
q = Heat absorbed = 36.5 kJ = 36500J
m = Mass of water = 275 g
c = Specific heat capacity of water = 
= change in temperature = ? °C
Putting values in above equation, we get:

Hence, the temperature increase will be 31.70°C.
Ok so first you need to figure out the energy of ONE photon with that wavelength. Using E=hc/lambda, you get E= 1.99 * 10^-20 J/photon. Now, how many photons do you need to add up to get to one kilojoule=1000 joules? 1000J / (1.99 * 10^-20 J/photon) = approximately 5 * 10^22 photons
hope this helps
It would be the change in pressure that would <span>increase the amount of gas able to be dissolved in a given amount of liquid water. Increasing the pressure of a system would allow more gas to be dissolved into a liquid. Hope this answers the question. Have a nice day.</span>
Suppose protons were emitted rather than electrons then it affects the experiment as the mean velocity of proton will be less then mean velocity electron .
The mass of proton is greater than the mass of electrons but charge of electron is equal to the charge of proton . So , due to difference in the mass of electron and proton there will be some effects. We can conserve the electric energy which is equal to the qe .
The kinetic energy = 1/2
Now changing the electric potential energy into kinetic energy
v = √2qe/m
The mean velocity of proton will be less then mean velocity electron .
To learn more about proton
brainly.com/question/1252435
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Answer:
Option c → 8:1
Explanation:
This is the reaction:
C₅H₁₂ + 8O₂ → 10CO₂ + 6H₂O
1 mol of pentane needs 8 moles of oxygen to be combusted and this combustion produces 10 mol of carbon dioxide and 6 moles of water.
To determine the ratio, look the stoichiometry.
For every 8 moles of oxygen, I need 1 mole of pentane gas.