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son4ous [18]
3 years ago
14

The water cycle always follows the same pattern

Chemistry
2 answers:
strojnjashka [21]3 years ago
6 0
If it is a true or false questions, the answer is TRUE.

JulsSmile [24]3 years ago
6 0
The answer would be True
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In a covalent bond, the electrons are _____
Ivenika [448]

Explanation:

In a covalent bond the electrons are simultaneously attracted by the two atomic nuclei.

6 0
2 years ago
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1.0 gallon to mm<br>N.B 1 gallon=3.8L​
I am Lyosha [343]

Answer:

Gallon (US) to Milliliter Conversion Table

Gallon (US) [gal (US)] Milliliter [mL]

1 gal (US) 3785.411784 mL

2 gal (US) 7570.823568 mL

3 gal (US) 11356.235352 mL

5 gal (US) 18927.05892 mL

4 0
2 years ago
Fish breathe the dissolved air in water through their gills. Assuming the partial pressures of oxygen and nitrogen in air to be
amid [387]

Answer:

X(O₂) = 0.323

X(N₂) = 0.677

Explanation:

We have the partial pressures of oxygen (O₂) and nitrogen (N₂):

P(O₂) = 0.20 atm

P(N₂) = 0.80 atm

In order to solve the problem, you need the solubilities of each gas in water at 298 K. We can consider 1.3 x 10⁻³ mol/(L atm) for oxygen (O₂) and 6.8 x 10⁻⁴mol/(L atm) for nitrogen (N₂) from the bibliography.

s(O₂) = 1.3 x 10⁻³ mol/(L atm)

s(N₂) = 6.8 x 10⁻⁴mol/(L atm)

So, we calculate the concentration (C) of each gas as the product of its partial pressure (P) and the solubility (s):

C(O₂) = P(O₂) x s(O₂) = 0.20 atm x 1.3 x 10⁻³ mol/(L atm) = 2.6 x 10⁻⁴mol/L

C(N₂) = P(N₂) x s(N₂) = 0.80 atm x 6.8 x 10⁻⁴mol/(L atm) = 5.44 x 10⁻⁴ mol/L

In 1 liter of water, we have the following number of moles (n):

n(O₂) = 2.6 x 10⁻⁴ mol

n(N₂) = 5.44 x 10⁻⁴ mol

Thus, the total number of moles (nt) is calculated as the sum of the number of moles of the gases in the mixture:

nt = n(O₂) + n(N₂) = 2.6 x 10⁻⁴ mol + 5.44 x 10⁻⁴ mol = 8.04 x 10⁻⁴ mol

Finally, the mole fraction of each gas is calculated as the ratio between the number of moles of each gas and the total number of moles:

X(O₂) = n(O₂)/nt = 2.6 x 10⁻⁴ mol/(8.04 x 10⁻⁴ mol) = 0.323

X(N₂) = n(N₂)/nt = 5.44 x 10⁻⁴ mol/(8.04 x 10⁻⁴ mol) = 0.677

5 0
3 years ago
How many moles of carbon dioxide (CO2) are in a 22 gram sample?
Anvisha [2.4K]

Answer:

0.5 mole

Explanation:

C=12u

O=16u

1 mole carbon dioxide=44 grams

so 22grams = 0.5 mole

6 0
3 years ago
Applications of chemistry in medical field
OLga [1]

Answer:

Explanation:

Drug for the treatment of disease. Chemistry contributes to the preparation and use of materials for surgery (sutures, artificial skin, and sterile materials). ...

Surgical procedure. ...

Blood samples for laboratory testing. ...

Blood glucose testing device.

6 0
3 years ago
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