1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Trava [24]
3 years ago
14

Lenses are made to have different focal points. What two properties of a lens

Chemistry
1 answer:
Novay_Z [31]3 years ago
3 0
The correct answer is letter C
You might be interested in
If I have 0.275 moles of gas at a temperature of 75 K and a pressure of 1530 mmHg, what is the volume of the gas?
Maru [420]

Answer: The volume of the gas is 0.84 Liters

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1530 mm Hg = 2.01 atm     (760mmHg=1atm)

V = Volume of gas = ?

n = number of moles = 0.275

R = gas constant =0.0821Latm/Kmol

T =temperature =75K

V=\frac{nRT}{P}

V=\frac{0.275atm\times 0.0820 Latm/K mol\times 75K}{2.01atm}=0.84L

Thus the volume of the gas is 0.84 Liters

6 0
2 years ago
The wax of a burning candle is a fuel that combines with oxygen in the air. As the fuel is consumed, what happens to most of the
Molodets [167]
D. It is released as heat and light.
7 0
3 years ago
Read 2 more answers
The work function is the energy that must be supplied to cause the release of an electron from a photoelectric material. The cor
vladimir2022 [97]

Answer:

No photoelectric effect is observed for Mercury.

Explanation:

From E= hf

h= Plank's constant

f= frequency of incident light

Threshold Frequency of mercury= 435×10^3/ 6.6×10^-34 × 6.02×10^23

f= 11×10^14 Hz

The highest frequency of visible light is 7.5×10^14. This is clearly less than the threshold frequency of mercury hence no electron is emitted from the mercury surface

3 0
3 years ago
30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr
Alenkasestr [34]

Answer: Thus concentration of Ca(OH)_2 in mol/dm^3  is 0.011 and in g/dm^3 is 0.814

Explanation:

To calculate the concentration of Ca(OH)_2, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3         1cm^3=0.001dm^3

Putting values in above equation, we get:

1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3

The concentration in g/dm^3 is 0.011mol/dm^3\times 74g/mol=0.814g/dm^3

Thus concentration of Ca(OH)_2 is 0.011mol/dm^3 and 0.814g/dm^3

4 0
3 years ago
Must show units and how they cancelli 1.) 175 km to um 3.) 385 nm to dm 5.) 492 um tom 7.) 52 x 103 dm to mm 9.) 321x 1035 mm to
morpeh [17]

Explanation:

1.) 175 km to μm

1 km=10^9 \mu m

175 km=175\times 10^9\mu m=1.75\times 10^{11} \mu m

3.) 385 nm to dm

1 nm=10^{-8} dm

385 nm=385\times 10^{-8} dm=3.85\times 10^{-6} dm

5.) 492 μm  to m

1 μm =  10^{-6} m

492 \μm=492\times 10^{-6} m=4.92\times 10^{-4} m

7.) 52\times 10^3 dm to mm

1 dm = 100 mm

52\times 10^3 dm=52\times 10^3\times 100 mm=5.2\times 10^{6}dm

9.) 321\times 10^{35} mm to km

1 mm = 10^{-6} km

321\times 10^{35} mm=321\times 10^{35}\times 10^{-6} km=3.21\times 10^{31} km

11.) 456\times 10^3 m to km

m = 0.001 km

456\times 10^3m =456\times 10^3 m\times 0.001 km=456 km

13.) 422\times 10^3 m to nm

1 m = 10^{9} nm

422\times 10^3 m=422\times 10^3\times 10^{9} nm=4.22\times 10^{14} nm

15.) 4.87\times 10^{30} m to pm

1 m = 10^{12} pm

4.87\times 10^{30} m=4.87\times 10^{30}\times 10^{12} pm=4.82\times 10^{42} pm

17.) 5.26\times 10^3 m to um

1 m =  10^{6} \mu m

5.26\times 10^3 m=5.26\times 10^3\times 10^6 \mu m=5.26\times 10^{9} \mu m

19.) 1.25\times 10^{35}m to Mm

1 m =  10^{-6} Mm

1.25\times 10^{35} m=1.25\times 10^{35}\times 10^{-6} Mm=1.25\times 10^{-29} Mm

21.) 4.22\times 10^3 Tm to nm

1 Tm = 10^{21} nm

4.22\times 10^3 Tm=4.22\times 10^3\times 10^{21} nm=4.22\times 10^{24} nm

6 0
3 years ago
Other questions:
  • How much energy is required to heat the solid iron from 1535 ∘C to 2000 ∘C?
    11·1 answer
  • Low air pressure can cause
    8·1 answer
  • How does a buffer resist change in pH upon addition of a strong acid? The strong acid reacts with the strong base in the buffer
    12·1 answer
  • Define chemical change and give an example
    13·2 answers
  • Assuming ideal behavior, what is the freezing point of a 0.030 m solution of Al2(SO4)3 ?
    5·1 answer
  • Which is a component of John Dalton’s atomic theory?
    10·2 answers
  • what element is this atom? need the answer in 30 minutes. Feel free to answer the other questions. NEED HELP!
    9·2 answers
  • What is the mass of oxygen gas in a 12.2 L
    5·1 answer
  • A lake has a surface area of 16.0 square miles and an average depth of 49.0 feet.
    14·1 answer
  • Can someone answer these questions about the LACK OF CLEAN DRINKING WATER? PLS. I will give 30 pts.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!