Answer:
1.06 × 10^5 J
Explanation:
We have to use the formula;
log(k2/k1) = Ea/2.303 ×R (1/T1 - 1/T2)
Given that;
k1 = 1.10 × 10-4 s-1
k2= 1.02 × 10-3 s-1
Ea=?
R=8.314 Jmol-1K-1
T1= 470. °C
T2= 510. °C
Hence;
log(1.02 × 10-3 s-1/1.10 × 10-4 =Ea/2.303 ×8.314(1/470 -1/510)
0.9672 = Ea/19.122(2.13 - 1.96) × 10^-3
0.9672= Ea/19.122(0.17) × 10^-3
0.9672= 1.7 ×10^-4 Ea/19.122
19.122 × 0.9672 = 1.74 × 10^-4Ea
Ea= 19.122 × 0.9672/1.74 × 10^-4
Ea= 18.495/1.74 × 10^-4
Ea= 1.06 × 10^5 J
Answer:
I believe it's plasma, solid, liquid, gas.
Explanation:
<h2>plasma and solids consist of lots, one jumbled, one together. liquid is still quite a bit, and gas is everywhere but there isn't much in one.</h2>
Answer:
There are 1.253*10²⁴ particles in 2.080 moles
Explanation:
Avogadro's number is called the number of particles that make up a substance (usually atoms or molecules) that can be found in the amount of one mole. In other words, Avogadro's number is the number of molecules that one mole of any substance contains. Its value is 6.023 * 10²³ particles per mole.
So, you can apply a rule of three as follows: if 1 mole has 6.023*10²³ particles, then 2.080 moles, how many particles does it have?
amount of particles= 1.253*10²⁴ particles
<u><em>There are 1.253*10²⁴ particles in 2.080 moles</em></u>
Answer:
See explanation
Explanation:
We must take into account the order of stability of free radicals. The order of stability of free radicals is;
Tertiary>secondary>primary> methyl.
As a result of this, structure 1 involving a tertiary radical leads to the more abundant product as shown.