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Makovka662 [10]
3 years ago
13

2 unicellular no autotrophic It uses a flagellum. A. Kingdom animalia B. kingdom fungi B. kingdom plantae D. kingdom protista

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
8 0
I know the answer to the question
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Enter the appropriate symbol for an isotope of calcium-42 corresponding to the isotope notation AZX.
Vikki [24]
Answer is ₂₀⁴²Ca.<span>

In AZX notation
   A<span> - Represents the </span>mass number of atom.
         Mass number = number of protons + number of neutrons.
<span>         It is shown at the </span>above of the left side<span> of the atom.</span>
<span>         Here it is </span>42. 

<span>  </span>Z - Represents the atomic number.<span>
       Atomic number = number of protons.
       </span><span>It is shown at the</span> bottom line of the left side of the atom.<span>
       </span>Here it is 20.<span>
 
  X - </span>Represents the symbol of the atom.<span>
     <span>   </span></span>Here</span> X is Ca.<span>

</span>
5 0
3 years ago
Read 2 more answers
2. Determine the molarity of the NaOH solution in each trial. a. Trial 1 Molarity: b. Trial 2 Molarity: 3. Calculate the average
butalik [34]

Answer:

This question is incomplete

Explanation:

This question is incomplete but...

1) You can calculate the molarity of the NaOH for each trial by following the steps below.

The formula for Molarity (M) is

M = number of moles (n) ÷ volume (V)

where the unit of volume must be in Litres or dm³

The unit of molarity is mol/dm³ or mol/L or molar conc (M)

The final answer must have the unit of molarity

If the number of moles is not provided, look out for the mass of NaOH used and then calculate your number of moles (n) as

n = mass of NaOH used ÷ molar mass of NaOH

Where the atomic mass of sodium (Na) is 23, oxygen (O) is 16 and hydrogen (H) is 1. Hence, molar mass for NaOH is 23 + 16 + 1 = 40 g/mol

n = mass of NaOH used ÷ 40

2) Average Molarity will be (Trial 1 Molarity +Trial 2 Molarity) ÷ 2

Answer must be in mol/dm³ or mol/L or M

3) Label the volumentric flask containing the NaOH solution with the answer gotten from (2) above

3 0
3 years ago
Three beakers contain clear, colorless liquids. One beaker contains pure water, another contains salt water, and another contain
gladu [14]
Pure water may be identified by its density: it will have the lowwest density of the three solutions, given that the solutes (salt and sugar) increase the density (this is the easiests and quickest way).

You can also measure the freezing points or boling points to identify the pure water because the solutes depress the freezing points and increase the boling points.

To differentiate sugar water and salt water, you can probe which one conducts electricity, because salt water is a conductor (given that it ionizes into Na+ and Cl-) but sugar water is not a conductor.
6 0
3 years ago
Read 2 more answers
Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO
vlada-n [284]

Answer:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Best regards!

4 0
2 years ago
Which element is found in all the acids described in this section?
mixer [17]
Acids contain hydrogen!
8 0
2 years ago
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