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crimeas [40]
1 year ago
15

You discover a piece of jewelry that you think might be made of silver. You place the item on a balance and determine that it ha

s a mass of 12.2 grams. It displaces 1.9 cm 3 of water when placed in a graduated cylinder. Is this item made of pure silver? Show your work.
Chemistry
1 answer:
Amanda [17]1 year ago
4 0

No, this item is not made of pure silver because if it has been made from pure silver that it would have displaced only 1.16cm³ of water but due to the addition of some other low-density element it displaces 1.9cm³ of water.

<u>For pure silver</u>

density of pure silver is = 10.49 g/cm³

mass of silver = 12.2 gram

since, density = mass/volume

          volume = mass/density

                        = 12.2/10.49 cm³

                         = 1.16 cm³

But the actual displaced water is <u>1.9cm³</u>, which means some other element of lower density has been added.

Therefore, it is clear that the given jewelry is not made of pure silver.

Learn more about silver here:-brainly.com/question/17086277

#SPJ1

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The ________ of acids, buffers, enzymes, and water aids in the breakdown of food.
tatuchka [14]

The <u>secretion</u><u> </u>of acids, buffers, enzymes, and water aids in the breakdown of food.

The food moves through the gastrointestinal tract and breaks down into smaller particles for energy, cell repair, and growth.

Digestion begins when eating and chewing food with the help of teeth in the mouth, then it goes down to the small intestine.

While moving through the gastrointestinal tract it mixes with juices, acids, enzymes, and water which disintegrates the large molecules of food into smaller ones and makes it suitable for assimilation and absorption in the body.

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brainly.com/question/1385846

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7 0
1 year ago
Compute the molar enthalpy of combustion of glucose (C6 H12O6 ): C6 H12O6 (s) + 6 O2 (g) → 6 CO2 (g) + 6 H2 O (g) Given that com
lana66690 [7]

Answer:

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

Explanation:

Step 1: Data given

Mass of glucose = 0.305 grams

Combustion of 0.305 grams causes a raise of 6.30 °C

Calorimeter has a heat capacity of 755 J/°C

Molar mass of glucose = 180.2 g/mol

Step 2: The balanced equation

C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)

Step 3:

ΔH = (m * C * ΔT + c(calorimeter) * ΔT)

with m = mass of the solutin = 0.305 grams

with C = heat capacity of water = 4.184 J/g°C

with ΔT = the change in temperature = 6.30 °C

with c(calorimeter) = 755 J/°C

ΔH = 0.305 * 4.184 *6.30 + 755 * 6.30  = 4764.5 J ( negative because it's exothermic)

Step 4: Calculate moles of glucose

Moles glucose = mass glucose / Molar mass glucose

Moles glucose = 0.305 grams / 180.2 g/mol

Moles glucose = 0.00169 moles

Step 5: Calculate molar enthalpy

Molar enthalpy = -4764.5 J / 0.00169 moles

Molar enthalpy = - 2819254.2 J/moles = -2819.3 kJ/moles

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

5 0
3 years ago
For the reaction 2 HCl + Na2CO3 → 2 NaCl + H2O + CO2 8.0 moles of CO2 is collected at STP. What is the volume of CO2? 1. 57.6 L
Dmitry [639]

Answer:

Option 5. 179L

Explanation:

The reaction is:

2 HCl + Na₂CO₃ → 2NaCl + H₂O + CO₂

The amount of collected CO₂ is 8 moles.

We apply the Ideal Gases Law at STP

STP are 1 atm of pressure and 273K of T°

P . V = n . R . T

1atm . V = 8 mol .0.082L.atm/mol.K . 273K

V = (8 mol .0.082L.atm/mol.K . 273K) / 1 atm = 179 L

6 0
3 years ago
What happens when molecular compounds melt?
Harman [31]
Molecules arranged in regular pattern changes into an irregular pattern
6 0
3 years ago
Read 2 more answers
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

3 0
3 years ago
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