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Finger [1]
1 year ago
12

Select the correct answer from the drop-down menu. anne applies a force on a toy car and makes it move forward. what can be said

about the forces acting on the toy car at the moment anne applies the force? the forces acting on the toy car are .
Physics
1 answer:
nalin [4]1 year ago
6 0

Answer:

The forces could be gravity, friction between the car and the ground, the force Katie is applying and the normal reaction.

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The Force Of Gravity Acting On A Childs Mass On Earth Is 490 newtons whats the childs mass
Flauer [41]
Force of gravity on an object is the weight of the object and is given by mass times accerelation due to gravity. The accerelation due to gravity is the accerelation of an object in free fall and is given by 9.8m/s^2. Given that the force of gravity acting on a child's mass on earth is 490 newtns, i.e. F = mg which means that 490 newtons = 9.8 times mass. Therefore, mass of the child is 490 / 9.8 = 50 kg.
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3 years ago
I NEED THE RIGHT ANSWER ASAP NO LINKS !!!<br> This is a Science question
murzikaleks [220]

Answer:

Independent variable

Explanation:

The temperature of air inside the box depends on the time that the booxes sat on the window sill.

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2 years ago
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Read the following selections from the section "Mickey Guyton's Star-Spangled Banner."
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Answer:

C

Explanation:

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2 years ago
A 70.0 kg person jumping down from a 3.00 meter wall hits the ground at 7.70 m/s. He hits the ground with stiff legs and stops i
shusha [124]

Answer:

F_{net} = 24434.783\,N

Explanation:

Let consider that the person hit the ground in the negative direction. The physical model for the impact is modelled after the Impact Theorem:

m_{person}\cdot v + Imp = 0

The impact is:

Imp = - m_{person}\cdot v

Imp = - (70\,kg)\cdot (-7.70\,\frac{m}{s} )

Imp = 539\,N\cdot s

The force of impact is derived as follows:

F_{net} = \frac{Imp}{\Delta t}

F_{net} = \frac{539\,N\cdot s}{0.023\,s}

F_{net} = 24434.783\,N

3 0
3 years ago
c) An aluminum tea kettle with mass 1.10 kg containing 1.80 kg of water is placed on a stove. If no heat is lost to the surround
True [87]

Answer:

Q = 640425 J = 640.425 KJ

Explanation:

From the law of conservation of energy:

Heat Addition = Heat Gain of Water + Heat Gain of Aluminum Kettle

Q = m_wC_w\Delta T_w + m_aC_a\Delta T_a

where,

Q = Heat addition required = ?

m_w = mass of water =1.8 kg

m_a = mass of aluminum kettle = 1.1 kg

C_w = specific heat capacity of water = = 4200 J/kg.°C

C_a  = specific heat capacity of aluminum kettle = = 890 J/kg.°C

\Delta T_w = \Delta T_a = change in temperature of water and kettle = 95°C - 20°C = 75°C

Therefore,

Q = (1.8\ kg)(4200\ J/kg.^oC)(75^oC)+(1.1\ kg)(890\ J/kg.^oC)(75^oC)\\

Q = 567000 J + 73425 J

<u>Q = 640425 J = 640.425 KJ</u>

8 0
3 years ago
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