The solution to the given system of equation is (3, 3, 3)
<h3>Solving system of equations</h3>
Given the following system of equation expressed as:
2x-y+5z=16
X-6у +2z=-9
3x+4y- z=32
Multiply equation 2 by 2 to have:
2x-y+5z=16
2X-12у +4z=-18
Subtract
10y+z = 34 .........4
Similarly
3X-18у +6z=-27
3x+4y- z=32
Subtract
-22y+7z = -59 ........... 5
Equate 4 and 5
10y+z = 34 .........4 * 7
-22y+7z = -59 ........... 5 * 1
_______________________
70y+7z = 238
-22y+7z = -59
Subtract
92y = 297
y = 3
Recall that
10y+z = 34
10(3) + z = 34
z = 3
Since x - 6y +2z = -9
x-6(3)+2(3) = -9
x - 18 + 6 = -9
x = 3
Hence the solution to the given system of equation is (3, 3, 3)
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13. they are not, because the parentese's make it different by applying the order of operations to the two sections, rather than in a long line.
the first one is equal to 1/40 1/4 * 10 = 1/40
second one is equal to 3/8 10 / 40 / 2 *5 = .25 / 2 * 5 = 3/8
14. g + w = 40 since there are both grape and watermelon in the entire jar of 50
15. algebraic because it involves variables and not just numbers dependent on PEMDAS
You need to combine like terms. So...
12 + 3x - x - 12 = 2x
Answer:
C
Step-by-step explanation:
the answer is not revealed
