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babymother [125]
3 years ago
12

Imagine a sunny day at the pool. The sun is out and you are thinking about how the light travels from the sun and then hits the

water. How does the light react once it hits the water? Draw or insert a model (that you created not Googled) of what you think happens to the light as it hits the water in the space below. Make sure to include an explanation too. Use what you learned to help you.
Physics
2 answers:
Dovator [93]3 years ago
5 0

Answer:

it evaporats

Explanation:

because the sun is so hot that the water will turn into gas hope i helped

sesenic [268]3 years ago
4 0

Answer:

im pretty sure is reflects the water to objects appear blurrier than on land

Explanation:

PLS CORRECT ME IF I AM WRONG

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nlexa [21]

Question 9 is 100 N.

Question 10 is No, the bike's motion is not changing so it could be at rest or moving at a constant velocity.

Question 11 is Be doubled.

Question 12 is Ella is correct.

Hope i helped.

6 0
3 years ago
Read 2 more answers
Answer this question, please​
pashok25 [27]

Answer:

the correct answer is the 60

+ 20 + 60 \gamma  \beta

3 0
3 years ago
A major process by which the Sun's energy is transported around the Earth system?
Setler79 [48]
Is it Conduction. Here's my theory e<span>nergy is transferred between the earth's surface and the atmosphere by Conduction, Convection and Radiation.</span>
3 0
3 years ago
A layer of oil (n = 1.38) floats on an unknown liquid. A ray of light originates in the oil and passes into the unknown liquid.
Vinil7 [7]

Answer:

Refractive index of unknown liquid = 1.56

Explanation:

Using Snell's law as:

n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence  ( 65.0° )

{\theta_r} is the angle of refraction  ( 53.0° )

{n_r} is the refractive index of the refraction medium  (unknown liquid, n=?)

{n_i} is the refractive index of the incidence medium (oil, n=1.38)

Hence,  

1.38\times {sin65.0^0}={n_r}\times{sin53.0^0}

Solving for {n_r},

Refractive index of unknown liquid = 1.56

4 0
3 years ago
If a circuit has a power of 50 W with a current of 4.5 A, what is the resistance in the circuit?
lawyer [7]

Answer:

{ \rm{power, \: p = current \times p.d}} \\ { \rm{50 = 4.5 \times (current \times resistance)}} \\ { \rm{50 = 4.5 \times (4.5 \times r)}} \\ { \rm{resistance =  \frac{50}{ {4.5}^{2} } }} \\  \\ { \rm{resistance = 2.5 \:  ohms}}

8 0
2 years ago
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