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musickatia [10]
3 years ago
15

On a sunny day at the beach, the land heats up faster than the ocean. The warmer air over the land rises, so the cooler air over

the ocean rushes in to take its place. This creates a wind called a sea breeze. After sunset, the land cools faster than the water, so the air over the ocean is warmer. Describe what you think happens to the movement of air and the direction of the wind.
Physics
1 answer:
lisov135 [29]3 years ago
5 0
As opposed to what is mentioned as the sea breeze, what was being asked to describe is what is known to be as land breeze. If the sea breeze is a wind that comes from the sea to the land, then the land breeze is the wind that comes from the land going to the sea. The same concept applies. What happens is that when the warmer air over the ocean rises and the cooler air over land rushes in to replace the warmer air, the movement of the air comes at still and creates the breeze. The directions of the wind would also go towards the sea.
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A car accelerates from 2.3 to 27 m/sec in 9.8 seconds. Calculate its acceleration.<br> m/sec2
grin007 [14]
Acceleration = (27 - 2.3 ) / 9.8 = ....
6 0
3 years ago
Electrons are accelerated through a voltage difference of 230 kV inside a high voltage accelerator tube. What is the final kinet
Aliun [14]

Answer:

kinetic energy is 3.68 ×10^{-14} J

speed of these electrons is 0.5565 c

Explanation:

Given data

voltage difference = 230 kV

to find out

kinetic energy and speed of these electrons

solution

we know kinetic energy formula that is

kinetic energy = qv

kinetic energy = 1.6 ×10^{-19} × 230 × 10^{3}

kinetic energy = 3.68 ×10^{-14} J

and

speed of electron that is

kinetic energy = m1c² - m2 c²

here m1 = m / √(1-v/c)²

so

KE/mc²  = ( 1 / √(1-(v/c)² ) - 1

put value here

3.68 ×10^{-14} / (3× 10^8)²×9.11×10^{-31} = ( 1 / √(1-v/c)² ) - 1

0.448835223 = ( 1 / √(1-(v/c)² ) - 1

( 1 / √(1-(v/c)² ) = 0.448835223 + 1 = 1.448835223

√(1-(v/c)²  = 1 / 1.448835223 = 0.6902096

(v/c)² = 1 - 0.6902096 = 0.309790

v = 0.5565 c

speed of these electrons is 0.5565 c

5 0
3 years ago
Which of the following is the most likely global climate change?a.a decrease in the overall temperature of the Earthb.an increas
andrew11 [14]
I believe the answer is C. an increase in the number of cold climates
5 0
3 years ago
Read 2 more answers
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 35 ft/s. Its height
Svetllana [295]

Answer:

Part A:

(a): -121.26 ft/s.

(b): -121.13 ft/s.

(c): -121.052 ft/s.

(d): -121.026 ft/s.

Part B:

-121.00 ft/s.

Explanation:

Given that the height of the balloon after t seconds is

\rm y(t) = 35 t-26t^2.

The average velocity of an object is defined as the total distance traveled by the object divided by the time taken in covering that distance.

\rm v_{av} = \dfrac{y_2-y_1}{t_2-t_1}

where,

\rm y_2,\ y_1 are the positions of the object at time \rm t_1 and \rm t_2 respectively.

<h2><u>Part A:</u></h2><h2 />
  • For the average velocity for the time period beginning when t=3 and lasting .01 sec.

For this case,

\rm t_1 = 3\ sec.\\t_2 = 3+0.01\ sec = 3.01\ sec.\\\\Therefore, \\\\y_1 = 35\cdot 3-26\cdot 3^2=-129\ ft.\\y_2 = 35\cdot 3.01-26\cdot 3.01^2=-130.2126\ ft.\\\\\Rightarrow v_{av}=\dfrac{-130.2126-(-129)}{3.01-3}=-121.26\ ft/s.

  • For the average velocity for the time period beginning when t=3 and lasting .005 sec.

For this case,

\rm t_1 = 3\ sec.\\t_2 = 3+0.005\ sec = 3.005\ sec.\\\\Therefore, \\\\y_1 = 35\cdot 3-26\cdot 3^2=-129\ ft.\\y_2 = 35\cdot 3.005-26\cdot 3.005^2=-129.60565\ ft.\\\\\Rightarrow v_{av}=\dfrac{-129.60565-(-129)}{3.005-3}=-121.13\ ft/s.

  • For the average velocity for the time period beginning when t=3 and lasting .002 sec.

For this case,

\rm t_1 = 3\ sec.\\t_2 = 3+0.002\ sec = 3.002\ sec.\\\\Therefore, \\\\y_1 = 35\cdot 3-26\cdot 3^2=-129\ ft.\\y_2 = 35\cdot 3.002-26\cdot 3.002^2=-129.2421\ ft.\\\\\Rightarrow v_{av}=\dfrac{-129.2421-(-129)}{3.002-3}=-121.052\ ft/s.

  • For the average velocity for the time period beginning when t=3 and lasting .001 sec.

For this case,

\rm t_1 = 3\ sec.\\t_2 = 3+0.001\ sec = 3.001\ sec.\\\\Therefore, \\\\y_1 = 35\cdot 3-26\cdot 3^2=-129\ ft.\\y_2 = 35\cdot 3.001-26\cdot 3.001^2=-129.121\ ft.\\\\\Rightarrow v_{av}=\dfrac{-129.121-(-129)}{3.001-3}=-121.026\ ft/s.

<h2><u>Part B:</u></h2>

The instantaneous velocity of the balloon at the given time is defined as the rate of change of its position at that time.

\rm v(t) = \dfrac{dy}{dt}\\=\dfrac{d}{dt}\left ( 35 t-26t^2\right )\\\\=35-26\times 2t.\\\\At\ t=3,\\\\v(t)=35-26\times 2\times 3=-121.00\ ft/s.

<u>Note:</u><em> The negative sign with all the velocities indicates that the direction of these velocities are downwards.</em>

<em> </em>

8 0
4 years ago
If a 240 N force F1 is applied to the piston with the 4 cm diameter, what is the magnitude of the force F2 that can be resisted
egoroff_w [7]

Answer:

38.4 N.

Explanation:

From pascal's principle,

Pressure applied to the first piston = pressure applied to the second piston

F1/A1 = F2/A2 ....................... Equation 1

Where F1 = Force applied to the first piston, A1 = Area of the first piston, F2 = force applied to the second piston, A2 = Area of the second piston.

But,

A1 = πd₁²/4................... Equation 2

A2 = πd₂²/4............... Equation 3

Where d₁ and d₂ are the diameter of the first and second piston respectively.

Substitute equation 2 and equation 3 into equation 1

F1/πd₁²/4 = F2/πd₂²/4

F1/d₁² = F2/d₂² ................. Equation 4

make F2 the subject of the equation,

F2 = (F1×d₂)/d₁²................ Equation 5

Given: F1 = 240 N, d₁ = 4 cm, d₂ = 10 cm.

Substitute into equation 5

F2 = (240×4²)/10²

F2 = 38.4 N.

5 0
4 years ago
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