<h2>
Put x =
I write the sum of 6x and 2x is at least 39 .</h2>
Step-by-step explanation:
We have,,
6x and 2x
To find, the value of x = ?
According to question,
The sum of 6x and 2x is at least 39
∴ 6x + 2x = 39
⇒ 8x = 39
⇒ x = 
∴ The value of x = 
Thus, put x =
I write the sum of 6x and 2x is at least 39 .
Answer:
you did not finish what you were saying
If you look closely at the options, the first 3 options will not produce an image that will be in Quadrant II with the vertices coinciding HGFE.
But if you look at the 4th option, translating the points 8 units to the left will produce an image in Quadrant III. Reflecting the image across the x-axis will produce triangle HGFE.
Answer:
c(4) = -76
Step-by-step explanation:
c(x) x=4 so plug 4 in for x
-5(4)² + (4)
Do parentheses first so... 4² = 16
-5(16) + 4
-5(16) = -80
-80+4 = -76
c(4) = -76
Solution:
<u>To classify a triangle a </u><u>scalene right:</u>
- It must have different side lengths
- It must have a right angle
<u>This triangle is a </u><u>Scalene Right</u><u> because:</u>
- It has different side lengths.
- It has a right angle.
<u>In conclusion...</u>
This triangle is a Scalene Right.