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Mashutka [201]
4 years ago
7

The family decides to keep their monthly expenses the same and to put all of the extra income from the raise into savings. What

percentage of their new income is allocated to housing (rounded to the nearest percent)?
17%

18%

19%

21%
-----
Monthly Budget is $5,400
Insurance - 23%
Transportation - 11%
Childcare - 18%
Food - 14%
Housing - 19%
Savings - 1%
Taxes - 5%
Other Needs - 9%



Can you also do the other question?

The family decides to keep their monthly expenses the same and to put all of the extra income from the raise into savings. What percentage of their new income is allocated to insurance (rounded to the nearest percent)?

26%
23%
22%
21%
Mathematics
2 answers:
Phoenix [80]4 years ago
7 0

Answer:

For the first one the answer is: 17%

And for the second one the answer is 26%

Step-by-step explanation: I just did the Performance Task and these were correct I know I'm like super duper late but can I get brainliest. 尺蛾翅蛾

Alinara [238K]4 years ago
6 0

Answer:

I think the first one is 19 I'm sorry if thats wrong.

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A contractor is building a new subdivision on the outside of a city. He has started work on the first street and is planning for
ruslelena [56]

You can use those two given points of street 1 to form its equation, then can use the fact that parallel lines have same slope to find the equation of second street with the help of the point (1,5) which lies in second street.

The equation of the location of the second street in standard form is given as 2y = x + 9

<h3>What is the equation of a straight line passing through two given points?</h3>

Let the two given points be (a,b) and (c,d). Then the equation of straight line passing through these two points is given by:

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<h3>What is slope intercept form of equation of straight line?</h3>

y = mx + c is the slope intercept form of straight line where m is the slope and c is the y-intercept (where the straight line cut on y = c at y axis) of the given line.

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Firstly we will find the equation of straight line which represents street 1.

Since street 1 goes from point (-5,-6) and (3,-2), thus, its equation would be:

y - (-6) = \dfrac{-2- (-6)}{3-(-5)} (x -(-5))\\&#10;\\&#10;y + 6 = \dfrac{1}{2}(x+5)\\&#10;\\&#10;y + 6 = \dfrac{x}{2} + \dfrac{5}{2}\\\\&#10;y = \dfrac{x}{2} -\dfrac{7}{2}

Thus, this above equation represents equation of location of street 1. The slope is 1/2 and y-intercept is -7/2.

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y = \dfrac{1}{2}x + c

Since street 2 passes through (1,5)( x=  1, y = 5), thus, this point must satisfy above equation which represents all points lying on street 2.

Thus,

5 = \dfrac{1}{2} \times 1 + c\\\\&#10;c = 5 - \dfrac{1}{2} = \dfrac{9}{2}

Thus, the equation representing points on street 2 is given by:

y = \dfrac{x}{2} + \dfrac{9}{2}\\&#10;\\&#10;2y = x + 9

Learn more about equation of straight line here:

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