1. The decomposition of CaCO3 proceeds according to the following equation.
1 answer:
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<h2>Hello!</h2>
The answer is: -97.23° C
<h2>Why?</h2>Applying the Charles and Gay-Lussac's Law we have that:
Where:
<em>k </em>is the proportionality constant
<em>v</em> is the volume of the gas
<em>t</em> is the temperature of the gas
We also have the following relation:
Since we need to know the new temperature (T2) we can find it using the last equation, so:
We are asked to find the temperature in Celsius degrees, we must convert the result:
Therefore, the temperature is -97.23° C
Have a nice day!