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3 years ago

2. If you have an unknown quantity of gas at a pressure of 1.2atm, a volume of 31 L, and a

Chemistry

1 answer:

Arturiano [62]3 years ago

8 0

Answer:

1.259 mol

Explanation:

Given data:

Pressure of gas = 1.2 atm

Volume of gas = 31 L

Temperature of gas = 87°C

Number of moles = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will convert the temperature.

87+273 = 360 K

by putting values,

1.2 atm × 31 L = n×0.0821 atm.L/ mol.K × 360 K

37.2 atm.L = n× 29.556 atm.L/ mol

n = 37.2 atm.L / 29.556 atm.L/ mol

n = 1.259 mol

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Determine the number of moles of C5H12 that are contained in 357.4 g of the compound.

AlladinOne [14]

Answer: 4.96 moles

Explanation:

C5H12 is the chemical formula for pentane, the fifth member of the alkane family.

Given that,

number of moles of C5H12 = ?

Mass in grams = 357.4 g

Molar mass of C5H12 = ?

To get the molar mass of C5H12, use the atomic mass of carbon = 12g; and Hydrogen = 1g

i.e C5H12 = (12 x 5) + (1 x 12)

= 60g + 12g

= 72g/mol

Now, apply the formula

Number of moles = Mass / molar mass

Number of moles = 357.4g / 72g/mol

= 4.96 moles

Thus, 4.96 moles of C5H12 that are contained in 357.4 g of the compound.

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3 years ago

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa. If Po2 =

HACTEHA [7]

Answer:

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa.

<u>The pressure for oxygen is 3 kPa</u>

Explanation:

According to Dalton's Law of Partial Pressure total exerted by the mixture of non-reacting gases is equal to sum of the partial pressure of each gas.

$P_{total}=P_{1}+P_{2}+P_{3}$

So,

For , a gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure:

$P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}$

$P_{total} = 32.5kPa$

$P_{O_{2}} = 6.5kPa$

$P_{N_{2}} = 23.0kPa$

Insert the values in :

$P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}$

$32.5 kPa = 6.5 kPa + 23.0 kPa +P_{CO_{2}}$

$32.5 kPa = 29.5 kPa +P_{CO_{2}}$

$P_{CO_{2}}= 32.5 - 29.5$

$P_{CO_{2}}= 3kPa$

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3 years ago

In lab, a dialysis bag was filled with a 10% sucrose solution and placed in an unlabeled beaker filled with clear liquid. The di

DaniilM [7]

Answer:

Of lower concentration or less concentrated

Explanation:

Osmosis is the movement of solvent from a region of lower concentration of solute to a region of higher concentration of solute through a semipermeable membrane in order to equalize the concentration of the solutions on both sides.

Since the membrane of the bag is semipermeable, then the fact that the bag in the beaker decreased in size, lost volume, and became flaccid indicates that the solution in the bag is of lower solute concentration than the solution in the beaker hence the movement of water molecules into the beaker by osmosis.

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3 years ago

Consider the following system at equilibrium:A(aq)+B(aq) <---> 2C(aq)Classify each of the following actions by whether it

velikii [3]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On addition of reactant at equilibrium shifts the equilibrium in forward direction.
On addition of product at equilibrium shifts the equilibrium in backward direction.
On removal of reactant at equilibrium shifts the equilibrium in backward direction.
On removal of product at equilibrium shifts the equilibrium in forward direction.

$A(aq)+B(aq)\rightleftharpoons 2C(aq)$

Reactants = A , B

Product = C

1. Increase A

On increasing the amount of A at equilibrium will shift the equilibrium in forward or rightward direction.

2. Increase B

On increasing the amount of B at equilibrium will shift the equilibrium in forward or rightward direction.

3. Increase C

On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.

4. Decease A

On decreasing the amount of A at equilibrium will shift the equilibrium in backward or leftward direction.

5. Decease B

On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.

6. Decease C

On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.

7. Double A and Halve B

Equilibrium constant of the reaction = K

$K=\frac{[C]^2}{[A][B]}$

On doubling A and halving B, equilibrium constant of the reaction = K'

$K'=\frac{[C]^2}{[2A][\frac{B}{2}]}=\frac{[C]^2}{[A][B]}$

The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.

8. Double both B and C

Equilibrium constant of the reaction = K

$K=\frac{[C]^2}{[A][B]}$

On doubling B and C, equilibrium constant of the reaction = K'

$K'=\frac{[2C]^2}{[A][2B]}=\frac{4[C]^2}{[A][2B]}=\frac{2[C]^2}{[A][B]}$

K' = 2 K

The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.

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3 years ago

What occurs when a 35-gram aluminum cube at 100.°C is placed in 90. grams of water at 25°C in an insulated cup?

posledela

Heat always flows from hot to cold. The aluminum is hotter than the water in the cup so the answer is 2: The heat is transferred from the aluminum to the water, and the temperature of the water increases.

8 0

3 years ago