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denpristay [2]
3 years ago
6

2. If you have an unknown quantity of gas at a pressure of 1.2atm, a volume of 31 L, and a

Chemistry
1 answer:
Arturiano [62]3 years ago
8 0

Answer:

1.259 mol

Explanation:

Given data:

Pressure of gas = 1.2 atm

Volume of gas = 31 L

Temperature of gas = 87°C

Number of moles = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

87+273 = 360 K

by putting values,

1.2 atm × 31 L = n×0.0821 atm.L/ mol.K   × 360 K

37.2 atm.L = n× 29.556 atm.L/ mol

n = 37.2 atm.L / 29.556 atm.L/ mol

n = 1.259 mol

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Answer:Hope this helps!

Explanation:

You can use a flame test to help identify the composition of a sample. The test is used to identify metal ions (and certain other ions) based on the characteristic emission spectrum of the elements. The test is performed by dipping a wire or wooden splint into a sample solution or coating it with the powdered metal salt. The color of a gas flame is observed as the sample is heated. If a wooden splint is used, it's necessary to wave the sample through the flame to avoid setting the wood on fire. The color of the flame is compared against the flame colors known to be associated with the metals.

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What is the formula for silicon tetrabromide?
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Explanation:

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hope this helps :)

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3 years ago
What is conductivity? How is it measured?
horrorfan [7]

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Explanation:

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2 years ago
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Consider a solution that is 1.3×10−2 M in Ba2+ and 2.0×10−2 M in Ca2+. Ksp(BaSO4)=1.07×10−10 Ksp(CaSO4)=7.10×10−5 If sodium sulf
skad [1K]

Answer:

Explanation:

Ksp(BaSO4)=1.07×10−10

BaSO₄ → Ba²⁺ + SO₄²⁻

1.07×10⁻¹⁰ = ( Ba²⁺) × ( SO₄²⁻)

but Ba²⁺ = 1.3×10⁻² M

1.07×10⁻¹⁰  = 1.3×10⁻² M × ( SO₄²⁻)

( SO₄²⁻)  = 1.07×10⁻¹⁰  / 1.3×10⁻² = 0.823 × 10⁻⁸ M

while Ksp(CaSO4)=7.10×10−5

CaSO₄ → Ca²⁺ + SO₄²⁻

7.10×10⁻⁵ = 2.0×10⁻² × ( SO₄²⁻)

( SO₄²⁻)  = 7.10×10⁻⁵  /  2.0×10⁻² = 3.55 × 10⁻³ M

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