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3 years ago

A sample of a gaseous substance at 25 celcius and 0.862 atm has a density of 2.26 g/l. what is the molecular weight

Chemistry

1 answer:

faust18 [17]3 years ago

5 0

Molecular weight = 2 * vapour density at STP.

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Serjik [45]

Answer:

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Explanation:

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3 years ago

The total pressure of gases a, b, and c in a closed container is 4.1 atm. if the mixture is 36% a, 42% b, and 22% c by volume, w

Natali [406]

The partial pressure of gas C is 0.902 atm

calculation

partial pressure of gas c =[( percent by volume of gas C / total percent) x total pressure]

percent by volume of gas C= 22%

Total percent = 36% +42% + 22% = 100 %

Total pressure = 4.1 atm

partial pressure of gas C is therefore = 22/100 x 4.1 atm = 0.902 atm

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3 years ago

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ikadub [295]

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3 years ago

How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide

Marat540 [252]

Answer:

$\boxed{\text{2.00 mol}}$

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r: 58.32

Mg(OH)₂ + … ⟶ … + 2HOH

m/g: 58.3

(a) Moles of Mg(OH)₂

$\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}$

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

$\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}$

The reaction will form $\boxed{\textbf{2.00 mol}}$ of water.

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3 years ago

What are the answers to these questions

Virty [35]

Answer:

Explanation:

So basically it just asking you question about that surtain subject .

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3 years ago