A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if
1 answer:
<h2>Hello!</h2>
The answer is: -97.23° C
<h2>Why?</h2>Applying the Charles and Gay-Lussac's Law we have that:
Where:
<em>k </em>is the proportionality constant
<em>v</em> is the volume of the gas
<em>t</em> is the temperature of the gas
We also have the following relation:
Since we need to know the new temperature (T2) we can find it using the last equation, so:
We are asked to find the temperature in Celsius degrees, we must convert the result:
Therefore, the temperature is -97.23° C
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Answer:
Explanation:
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In this case, since this is a system in which the water is heated up and the metal is cooled down in a calorimeter which is not affected by the heat lose-gain process, we can infer that the heat lost by the metal is gained be water, it means that we can write:
Thus, in terms of masses, specific heats and temperatures we can write:
Whereas the equilibrium temperature is the given final temperature of 28.4 °C and we can compute the specific heat of the metal as shown below:
Plugging the values in and since the density of water is 1.00 g/mL so the mass is 80.0g, we obtain:
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