Question

A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if

Answer 1

Hello!

The answer is: -97.23° C

Why?

Applying the Charles and Gay-Lussac's Law we have that:

$\frac{V}{T}=k$

Where:

k is the proportionality constant

v is the volume of the gas

t is the temperature of the gas

We also have the following relation:

$\frac{V1}{T1}=\frac{V2}{T2}$

Since we need to know the new temperature (T2) we can find it using the last equation, so:

$\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K$

We are asked to find the temperature in Celsius degrees, we must convert the result:

$Celsius=K-273.15=175.92-273.15=-97.23$

Therefore, the temperature is -97.23° C

Have a nice day!