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3 years ago

A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if

Chemistry

1 answer:

BigorU [14]3 years ago

6 0

<h2>Hello!</h2>

The answer is: -97.23° C

Applying the Charles and Gay-Lussac's Law we have that:

$\frac{V}{T}=k$

Where:

<em>k </em>is the proportionality constant

<em>v</em> is the volume of the gas

<em>t</em> is the temperature of the gas

We also have the following relation:

$\frac{V1}{T1}=\frac{V2}{T2}$

Since we need to know the new temperature (T2) we can find it using the last equation, so:

$\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K$

We are asked to find the temperature in Celsius degrees, we must convert the result:

$Celsius=K-273.15=175.92-273.15=-97.23$

Therefore, the temperature is -97.23° C

Have a nice day!

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