I think the answer you have selected is right, I'm not sure tho
"0.538 g" would be the mass of the water.
Given values are:
Hydrated salt,
Anhydrous salt,
→ The mass of water lost by the salt will be:
= 
By substituting the given values, we get\
= 
= 
Thus the above answer is appropriate.
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Answer
is: the final pressure of the gas is closest to 3,17 atm.
<span><span>
p</span>₁ =
3,2 atm.</span><span>
T₁ =
310 K.</span><span>
V₁ =
6 L.</span><span>
p₂ = ?</span><span>
T₂ =
410K.</span><span>
V₂ = 8,0 L.</span><span>
<span>Use combined gas law - the volume of amount of gas is proportional to the ratio of
its Kelvin temperature and its pressure.</span><span>
p</span></span><span>₁V₁/T₁ =
p₂V₂/T₂.</span><span>
<span>3,2 atm · 6,0 L ÷ 310 K = p</span>₂ · 8,0 L ÷ 410 K.</span><span>
0,0619 = 0,0195p</span><span>₂.</span><span>
p</span><span>₂ =
3,17 atm.</span>
Answer: The boiling point of water at 81 kPa will be 298.17 K.
Explanation:
The boiling point of water is 373 K at atmospheric pressure. So, to calculate the boiling point at 81 kPa, we use the law given by Gay-Lussac.
Gay-Lussac Law states that pressure is directly proportional to the temperature when volume and moles remain constant.
Mathematically,

where,
= Initial pressure and temperature
= Final pressure and temperature
We are given:

Putting values in above equation, we get:

Hence, the boiling point of water at 81 kPa will be 298.17 K.
Because it doesn't get direct sunlight so it gets cool