Hello there!
Sedimentary rocks are formed due to layers so the answer is A.
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-HuronGirl
Answer:
new substances formed, as evidenced by the color changes and bubbles. Some signs of a chemical change are a change in color and the formation of bubbles. The five conditions of chemical change: color chage, formation of a precipitate, formation of a gas, odor change, temperature change.
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Question is incomplete, complete question is;
A 34.8 mL solution of
(aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).
![H_2SO_4(aq)+2NaOH(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)](https://tex.z-dn.net/?f=H_2SO_4%28aq%29%2B2NaOH%28aq%29%5Crightarrow%20Na_2SO_4%28aq%29%2B2H_2O%28l%29)
If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of
? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.
Answer:
0.044 M is the molarity of
(aq).
Explanation:
The reaction taking place here is in between acid and base which means that it is a neutralization reaction .
To calculate the concentration of acid, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is ![H_2SO_4](https://tex.z-dn.net/?f=H_2SO_4)
are the n-factor, molarity and volume of base which is NaOH.
We are given:
![n_1=2\\M_1=?\\V_1=34.8 mL\\n_2=1\\M_2=0.15 M\\V_2=20.4 mL](https://tex.z-dn.net/?f=n_1%3D2%5C%5CM_1%3D%3F%5C%5CV_1%3D34.8%20mL%5C%5Cn_2%3D1%5C%5CM_2%3D0.15%20M%5C%5CV_2%3D20.4%20mL)
Putting values in above equation, we get:
![2\times M_1\times 34.8 mL=1\times 0.15 M\times 20.4 mL\\\\M_1=\frac{1\times 0.15 M\times 20.4 mL\times 10}{2\times 34.8 mL}=0.044 M](https://tex.z-dn.net/?f=2%5Ctimes%20M_1%5Ctimes%2034.8%20mL%3D1%5Ctimes%200.15%20M%5Ctimes%2020.4%20mL%5C%5C%5C%5CM_1%3D%5Cfrac%7B1%5Ctimes%200.15%20M%5Ctimes%2020.4%20mL%5Ctimes%2010%7D%7B2%5Ctimes%2034.8%20mL%7D%3D0.044%20M)
0.044 M is the molarity of
(aq).
A) 15.9 mL I hope it is if not I’m sorry