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3 years ago

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PLEASE HELP ME FAST!! How many moles are contained in 500 mL of a 3.5M NaOH solution?

1 answer:

viva [34]3 years ago

5 0

Answer:

1.75moles

Explanation:

Molarity = number of moles (n) ÷ volume (V)

According to the information given in this question,

V = 500mL = 500/1000 = 0.500L

n = ?

Molarity = 3.5M

Using Molarity = n/V

number of moles (n) = V × molarity

n = 0.5 × 3.5

n = 1.75moles.

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<h3>Further explanation </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:

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$\large {\boxed {\bold {PV = nRT}}}$

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V = volume, liter

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R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

To choose the formula used, we refer to the data provided

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T= 10 +273.15 = 373.15 K

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Red box

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