The function f(x) = 6^(x)-2 has an x-intercept at approximately <span>(0.39, 0)
f(x) = 0 = 6^(x) - 2
2 = 6^(x)
log(2)/log(6)= x
x = 0.3868 = 0.39</span>
The answer to this question is A) (0.39, 0).
Answer:
1.-3
2.0
Step-by-step explanation:
5-(-1)/1-3
6/-2
-3
-5-(-5)/-2-(-4)
0/-2+4
0/2
0
Substituting the data points into the model:
f(x)= -x2 + 2x -3
f(-2)=-11
f(0)=-3
f(1)=-2
f(3)=-6
f(5)=-18
So A is the right ans.
Answer:
A tree with a height of 6.2 ft is 3 standard deviations above the mean
Step-by-step explanation:
⇒
statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)
an X value is found Z standard deviations from the mean mu if:

In this case we have: 

We have four different values of X and we must calculate the Z-score for each
For X =5.4\ ft

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.
⇒
statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean.
(FALSE)
For X =4.6 ft

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean
.
⇒
statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean
(FALSE)
For X =5.8 ft

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.
⇒
statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean.
(TRUE)
For X =6.2\ ft

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.