Answer:
Θ = 46°
Step-by-step explanation:
the angle between a tangent and a radius at the point of contact is 90° , so
∠ ABO = 90°
since OB = OD ( radii of circle ) then Δ BOD is isosceles and
∠ OBD = ∠ ODB = 22°
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ AOB is an exterior angle of the triangle , then
∠ AOB = 22° + 22° = 44°
the sum of the 3 angles in Δ AOB = 180° , then
Θ + 44° + 90° = 180°
Θ + 134° = 180° ( subtract 134° from both sides )
Θ = 46°
Answer:

Step-by-step explanation:
Given
The attached rhombus
Required
The area
First, calculate the length of half the vertical diagonal (x).
Length x is represented as the adjacent to 60 degrees
So, we have:

Solve for x


So:


At this point, we have established that the rhombus is made up 4 triangles of the following dimensions


So, the area of the rhombus is 4 times the area of 1 triangle




Answer:
Third answer! Data varies!
Answer:
-1.2
Step-by-step explanation:
3.8-5=-1.2
lmk if this is right
hope it helped
4(5x-20)=-20
20x-80=-20
20x=60
x=3