The amount of heat that could be removed by 20.0 g of ethyl chloride is 8.184 kJ.
<h3>How do we calculate required heat?</h3>
Required amount of heat which can be removed for the vaporization will be calculated as:
Q = (n)(ΔHv), where
- n = moles of ethyl chloride
- ΔHv = heat of vaporization = 26.4 kj/mol
Moles will be calculated as:
n = W/M, where
- W = given mass of ethyl chloride = 20g
- M = molar mass of ethyl chloride = 64.51 g/mol
n = 20 / 64.51 = 0.31 mol
On putting all these values in the above equation, we get
Q = (0.31)(26.4) = 8.184 kJ
Hence involved amount of heat is 8.184 kJ.
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Chemical Bond
because they are chemically bonding
Answer : The correct option is (A) Hydrogen region of the molecule.
Explanation :
As we know that the water molecule has two hydrogen atom and one oxygen atom. The hydrogen atom has partial positive charge and oxygen has partial negative charge.
In the charged plate, the negative attracts positive and positive attracts negative. So, the hydrogen atom attracted to the negative plate and the oxygen atom attracted to the positive plate.
When water molecule placed between oppositely charged metal plates which is positively charged, then the hydrogen atom which is positively charged attracted towards the negative plate.
Answer:
d
Explanation:
Hope this helps and have a great day!!!
