Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
Answer:
B = 15
Step-by-step explanation:
<u>Combine multiplied terms into a single fraction</u>
6 + 2b/5 = 12
<u>Subtract 6 from both sides</u>
6 + 2b/5 <em>(-6)</em> = 12 <em>(-6) </em>= 2b/5 = 6
<u>Multiply all terms by the same value to eliminate fraction denominators</u>
2b/5 <em>( x 5) </em>= 6<em> (x 5)</em>
<em />
<u>Simplify</u>
2b = 30
Answer:
b = 1, c = -1 and d = 4
Step-by-step explanation:
To solve this question the rule of multiplicity of a polynomial is to be followed.
If the multiplicity of a polynomial is even at a point, graph of the polynomial will touch the x-axis.
If the multiplicity of the polynomial is odd, graph will cross the x-axis at that point.
From the graph of function 'f',
f(x) = (x - b)(x - c)²(x - d)³
Since, graph of the function 'f' crosses x-axis at x = 1 and x = 4, multiplicity will be odd and touches the x-axis at x = -1 multiplicity will be even.
So the function will be,
f(x) = (x - 1)[x - (-1)]²(x - 4)³
Therefore, b = 1, c = -1 and d = 4 will be the answer.
Answer:
9 x + 42.
Step-by-step explanation:
