What x rays travel at the speed of

A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg

Dahasolnce [82]

Answer:

The 5 kg ball moves 3.78 m/s to the left, and the 4 kg ball moves 7.22 m/s to the right.

Explanation:

Momentum before = momentum after

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(5 kg) (6 m/s) + (4 kg) (-5 m/s) = (5 kg) v₁ + (4 kg) v₂

10 m/s = 5 v₁ + 4 v₂

Assuming an elastic collision, kinetic energy is conserved.

½ m₁ u₁² + ½ m₂ u₂² = ½ m₁ v₁² + ½ m₂ v₂²

m₁ u₁² + m₂ u₂² = m₁ v₁² + m₂ v₂²

(5 kg) (6 m/s)² + (4 kg) (-5 m/s)² = (5 kg) v₁² + (4 kg) v₂²

280 m²/s² = 5 v₁² + 4 v₂²

Substituting:

v₂ = (10 − 5 v₁) / 4

280 = 5 v₁² + 4 [(10 − 5 v₁) / 4]²

280 = 5 v₁² + (10 − 5 v₁)² / 4

1120 = 20 v₁² + (10 − 5 v₁)²

1120 = 20 v₁² + 100 − 100 v₁ + 25 v₁²

0 = 45 v₁² − 100 v₁ − 1020

0 = 9 v₁² − 20 v₁ − 204

0 = (9 v₁ + 34) (v₁ − 6)

v₁ = -3.78 m/s or 6 m/s

u₁ = 6 m/s, so v₁ = -3.78 m/s. Solving for v₂:

v₂ = (10 − 5 v₁) / 4

v₂ = 7.22 m/s

The 5 kg ball moves 3.78 m/s to the left, and the 4 kg ball moves 7.22 m/s to the right.

6 0

3 years ago

An ocean wave traveling in one direction has a wavelength of 1.0 m and a frequency of 1.25 Hz. Take the direction of wave propag

aliina [53]

Answer:

a) $v=1*1.25=1.25\: m/s$

b) $y(x,t)=2sin(2\pi( x-1.25 t)$

c) $y(3,10)=1.73 m$

Explanation:

a) The speed of a wave is given by the following equation:

$v=\lambda f$

Where:

λ is the wavelength

f is the frequency

$v=1*1.25=1.25\: m/s$

b) The harmonic wave has the following equation:

$y=Asin(kx-\omega t)$

A is the amplitude (2 m)

k is the wavenumber (2π/λ)

ω is the angular frequency (2πf)

$y(x,t)=2sin(2\pi x-2\pi*1.25 t)$

$y(x,t)=2sin(2\pi( x-1.25 t)$

c) Here we need to find the heigth at x=3 m and t =10 s, so we need to find y(3,10).

$y(3,10)=2sin(2\pi(3-1.25*10)$

$y(3,10)=1.73 m$

I hope it helps you!

6 0

3 years ago

A 45-kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is above the bar is 1.1 m/s. Neglect air resistan

Lubov Fominskaja [6]

The altitude or height of the pole vaulter as she crosses the bar is 4.04 m.

<h3>What is the height of the pole vaulter?</h3>

The height of the pole vaulter is determined from the change in kinetic energy which is equal to the potential energy at that height.

Potential energy = Change in kinetic energy

mgh = m(v - u)²/2

h = (v - u)²/2g

h = (10 - 1.1)²/2 * 9.8

h = 4.04 m.

In conclusion, the height is determined from the potential energy at that height.

Learn more about potential energy at: brainly.com/question/14427111

#SPJ1

7 0

2 years ago

The police car with its 300-Hz siren is moving away from the warehouse at a speed of 16.0 m/s . . . What frequency does the driv

bazaltina [42]

Frequency heard by listener: fl = ?
frequency of source: fs = 300 Hz
velocity of listener: vl = 16 m/s
velocity of source: vs = 0
velocity of sound in air: c = 344 m/s

fl = fs [(c – vl)/c] = 300[(344-16)/344]
 =286.04 Hz

8 0

3 years ago

Read 2 more answers

Suppose a truck has a momentum of 40,120 kg • and a mass of 1,180 kg. What is the truck’s velocity?

gladu [14]

Answer:

The velocity of the truck is 34 m/s.

Explanation:

The momentum (p) of an object is the product of its mass (m) and its velocity (v) which can be written as:

p = mv

Here in this problem, we are given a truck which has a momentum of 40120 kg and a mass of 1180 kg and we are to find its velocity.

So substituting the given values in the above formula to find the velocity of the truck.

Truck's velocity = $\frac{40120}{1180}$ = 34 m/s.

3 0

3 years ago