Answer:
nine times as much.
Explanation:
K.E of A = 9 times K.E of B
Answer:
Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz
Explanation:
Given data
Source Frequency fs=600Hz
Length r=1.0m
RPM=100 rpm
The speed of the generator is calculated as:
![v_{s}=rw\\v_{s}=r(2\pi f)](https://tex.z-dn.net/?f=v_%7Bs%7D%3Drw%5C%5Cv_%7Bs%7D%3Dr%282%5Cpi%20f%29)
Substitute the given values
![v_{s}=(1.0m)2\pi (\frac{100}{60}rev/s )\\v_{s}=10.47m/s](https://tex.z-dn.net/?f=v_%7Bs%7D%3D%281.0m%292%5Cpi%20%28%5Cfrac%7B100%7D%7B60%7Drev%2Fs%20%29%5C%5Cv_%7Bs%7D%3D10.47m%2Fs)
For approaching generator the frequency is calculated as:
![f_{+}=\frac{f_{s}}{1-\frac{v_{s}}{v} }\\f_{+}=\frac{600Hz}{1-\frac{10.47m/s}{343m/s} } \\f_{+}=620Hz](https://tex.z-dn.net/?f=f_%7B%2B%7D%3D%5Cfrac%7Bf_%7Bs%7D%7D%7B1-%5Cfrac%7Bv_%7Bs%7D%7D%7Bv%7D%20%7D%5C%5Cf_%7B%2B%7D%3D%5Cfrac%7B600Hz%7D%7B1-%5Cfrac%7B10.47m%2Fs%7D%7B343m%2Fs%7D%20%7D%20%5C%5Cf_%7B%2B%7D%3D620Hz)
On the other hand,for the receding generator,Doppler's effect is expressed as:
![f_{-}=\frac{f_{s}}{1+\frac{v_{s}}{v} }\\f_{-}=\frac{600Hz}{1+\frac{10.47m/s}{343m/s} } \\f_{-}=580Hz](https://tex.z-dn.net/?f=f_%7B-%7D%3D%5Cfrac%7Bf_%7Bs%7D%7D%7B1%2B%5Cfrac%7Bv_%7Bs%7D%7D%7Bv%7D%20%7D%5C%5Cf_%7B-%7D%3D%5Cfrac%7B600Hz%7D%7B1%2B%5Cfrac%7B10.47m%2Fs%7D%7B343m%2Fs%7D%20%7D%20%5C%5Cf_%7B-%7D%3D580Hz)
Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz
<u>Answer:</u> The number of electrons in given amount of silver are ![1.87\times 10^{24}](https://tex.z-dn.net/?f=1.87%5Ctimes%2010%5E%7B24%7D)
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
We are given:
Given mass of silver = 7.1 g
Molar mass of silver = 107.87 g/mol
Putting values in above equation, we get:
![\text{Moles of silver}=\frac{7.1g}{107.87g/mol}=0.066mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20silver%7D%3D%5Cfrac%7B7.1g%7D%7B107.87g%2Fmol%7D%3D0.066mol)
Number of electrons in 1 atom of silver = 47
According to mole concept:
1 mole of an element contains
number of particles
So, 0.066 moles of silver will contain = -
number of electrons
Hence, the number of electrons in given amount of silver are ![1.87\times 10^{24}](https://tex.z-dn.net/?f=1.87%5Ctimes%2010%5E%7B24%7D)
1. 2+0.5+2.5= 3. 2km/hr average
2. 14-6=4seconds. 8m/s in 4s = 2m/s acceleration
3. 15m/s divided by 2.5 = 6m/s acceleration
Answer: D
Explanation: :) Just took the quizz