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zubka84 [21]
3 years ago
15

A 80-kg person sits on a 2.7kg chair. Each leg of the chair makes contact with the floor on a circle that is 1.3 cm in diameter.

Find the pressure exerted on the floor by each leg of the chair, assuming that the weight is evenly distributed.
Physics
2 answers:
Rashid [163]3 years ago
6 0

Answer:

need help with this 2

Explanation:

pls hellp

riadik2000 [5.3K]3 years ago
4 0

Explanation:

Assuming the chair has four legs,

Area = (πr²)

        = 1.33 m²

Pressure = Force/Area

               = 827/1.33

               = 621.8 Pa

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Answer:

\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}

Explanation:

<u>Dimensional Analysis</u>

It's given the relation between quantities A, B, and C as follows:

\displaystyle A=\frac{3}{2}B^mC^n

and the dimensions of each variable is:

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Substituting the dimensions into the relation (the coefficient is not important in dimension analysis):

\displaystyle L^2T^2=\left(LT^{-1}\right)^m\left(LT^2\right)^n

Operating:

L^2T^2=\left(L^mT^{-m}\right)\left(L^nT^{2n}\right)

L^2T^2=L^{m+m}T^{-m+2n}

Equating the exponents:

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Adding both equations:

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Solving:

n=4/3

m=2-4/3=2/3

Answer:

\mathbf{\displaystyle m=\frac{2}{3},\ n=\frac{4}{3}}

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