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Finger [1]
3 years ago
10

Ow does the light-collecting area of an 8-meter telescope compare to that of a 2-meter telescope?

Physics
1 answer:
fomenos3 years ago
6 0
<span>The area will be the square of the quotient of the amounts for each telescope. Comparing the two microscopes, the 8-meter model is 4 times larger than the 2-meter model. Squaring this value gives a ratio of 16 times the amount of visual area for the larger telescope.</span>
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Narysuj wykres zależności v(t) jeśli w chwili początkowej t=0 V=10m/s w każdej sekundzie szybkość zmniejsza się o 1m/s . Po jaki
irina1246 [14]

1) See graph in attachment

2) 10 s

3) 50 m

Explanation:

1)

In this problem, we have an object initially moving with a velocity of

v = 10 m/s

when the time is

t = 0 s

Then, we are told that the speed of the object is decreasing by 1 m/s every  second. This means that on a velocity-time graph, the motion will be represented by a straight line, starting from v = 10 when t = 0, and decreasing by 1 m/s every second.

The result can be found in the graph in attachment.

Moreover, we can also infer that the motion of the object is accelerated (because velocity is changing), and that the acceleration is constant and it is equal to

a=1 m/s^2

which is equivalent to the gradient of the line in the velocity-time graph.

2)

In this part, we want to find after what time the body will stop its motion.

To do that, we can use the following suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

In this problem:

u = 10 m/s is the initial velocity of the body

a=-1 m/s^2 is the acceleration

v = 0 m/s, because we want to find the time T at which the body will stop

Re-arranging the equation, we find:

T=-\frac{u}{a}=-\frac{10}{-1}=10 s

3)

In order to find the total distance covered by the body during its accelerated motion, we have to use another suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

In this problem:

u = 10 m/s is the initial velocity

a=-1 m/s^2 is the acceleration

t = 10 s is the time it takes for the body to stop (found in part 2)

Solving for s, we find the distance covered:

s=(10)(10)+\frac{1}{2}(-1)(10)^2=50 m

7 0
3 years ago
Calculate the number of free electrons and holes (in m-3) in an intrinsic semiconductor that has electron and hole mobilities of
allochka39001 [22]

Answer:

ni = 2.04e19

Explanation:

we know that in semiconductor like intrinsic, when electron leave the band, it leave a hole in valence band so we have

n = p = ni

from intrinsic carrier concentration

\sigma = n\left | e \right | \mu_e + n\left | e \right | \mu_h

\sigma = ni\left | e \right | \mu_e  + ni\left | e \right | \mu_h

\sigma = ni \left | e \right | ( \mu_e + \mu_h)

1.7 = ni * 1.6*10^{-19} * (.35 + .17)

ni = 2.014 *10^{19} m^{-3}

ni = 2.04e19

5 0
3 years ago
A car moving with a speed of 35 m/s sees a child standing in the
zlopas [31]

Answer:

2100 N

Explanation:

v = u + at \\ 0 = 35 + a(5) \\ a =  - 7m {s}^{ - 2}  \\ \\ net \: force \:  = ma \\  = (300)(7) \\  = 2100 \: newtons

6 0
3 years ago
What word does this define..<br><br>The distance traveled per unit of time​
nexus9112 [7]

Answer:..........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................Volosity???????

Explanation: THINK THATS IT PROBABLY MISPELLED IT SORRY IN ADVANCE IF WRONG

8 0
3 years ago
Read 2 more answers
How far will you travel if you walk for 10.0 minutes at a speed of 1.50 m/s?
fredd [130]

Answer:

15

Explanation:

distance = speed × time.

7 0
3 years ago
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