A) TOTAL Resistance = 41+18+120 = 179 ohms
<span>Current = V/R = 9 / 179 = 0.0503 A = 50.3 mA </span>
<span>B) V = I*R = .0503 * 41 = 2.06 V </span>
<span>C) V = I*R = .0503 * 18 = 0.91 V </span>
<span>D) V = I*R = .0503 * 120 = 6.03 V</span>
A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force. Forces only exist as a result of an interaction.
Answer:
c. joules
Explanation:
The rate at which a force displaces a mass a horizontal distance is measured in joules. In science, this phenomenon is known as work done.
Work done can be defined as the rate at which a force acting on an object or a body causes it to experience a displacement. The work done is a scalar quantity and is measured in joules (J).
Mathematically, work done is given by the formula;
Work done = force * distance
Where,
- F represents the force acting on a body.
- d represents the distance covered by the body.
<em>For example, a bull pulling a plough through a farm, a girl pushing a shopping cart down the aisle of a supermarket etc. </em>
Answer:
The mass of moon is 1/100 times and its radius 1/4 times that of earth. As a result, the gravitational attraction on the moon is about one sixth when compared to earth. Hence, the weight of an object on the moon is 1/6th its weight on the earth.
Answer:
45.89m/s²
Explanation:
Given
Distance S = 305m
Time t = 3.64s
To get the acceleration during this run, we will apply the equation of motion:
S = ut+1/2at²
Substitute the given parameters into the formula and calculate the value of a
305 = 0+1/2 a(3.64)²
304 = 1/2(13.2496)a
304 = 6.6248a
a = 304/6.6248
a = 45.89m/s²
Hence the average acceleration during this run is 45.89m/s²
