Answer:
Explanation:
For this exercise let's use hooke's law
F = - k x
where x is the displacement from the equilibrium position.
x = 
if we have several springs in series, the total displacement is the sum of the displacement for each spring, F the external force applied to the springs
x_ {total} = ∑ x_i
we substitute
x_ {total} = ∑ -F / ki
F / k_ {eq} = -F 
1 / k_ {eq} = ∑ 1 / k_i
if all the springs are the same
k_i = k
Answer:
Magnitude |VB| = 0.32 m/s
and
Direction is to the left
Explanation:
given data
glider A mass = 0.125 kg
glider B mass = 0.500 kg
glider A move = 0.960 m to the left
solution
we use here Conservation of momentum that is
M1 × U1 + M2 × U2 =M1 × V1 + M2 × V2 ........................1
put here value and we get
0.125 × 0 + 0.500 × 0 = 0.125 × 0.960 + 0.375 × VB
VB = −0.32 m/s
Magnitude |VB| = 0.32 m/s
and
Direction is to the left
Answer:
This is because when the pedal sprocket arms are in the horizontal position, it is perpendicular to the applied force, and the angle between the applied force and the pedal sprocket arms is 90⁰.
Also, when the pedal sprocket arms are in the vertical position, it is parallel to the applied force, and the angle between the applied force and the pedal sprocket arms is 0⁰.
Explanation:
τ = r×F×sinθ
where;
τ is the torque produced
r is the radius of the pedal sprocket arms
F is the applied force
θ is the angle between the applied force and the pedal sprocket arms
Maximum torque depends on the value of θ,
when the pedal sprocket arms are in the horizontal position, it is perpendicular to the applied force, and the angle between the applied force and the pedal sprocket arms is 90⁰.
τ = r×F×sin90⁰ = τ = r×F(1) = Fr (maximum value of torque)
Also, when the pedal sprocket arms are in the vertical position, it is parallel to the applied force, and the angle between the applied force and the pedal sprocket arms is 0⁰.
τ = r×F×sin0⁰ = τ = r×F(0) = 0 (torque is zero).
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the answer is A
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Answer:
250s
Explanation:
Given parameters:
Mass = 50kg
Speed = 10m/s
Force = 2N
Unknown:
Time the force was acting = ?
Solution:
To solve this problem, we use the equation of motion from the second law of Newton:
Ft = mV
F is the force
t is the time taken
m is the mass
V is the velocity
2 x t = 50 x 10
t = 250s
