To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.
In other words the acceleration can be described as

Where
G = Gravitational Universal Constant
M = Mass of Earth
r = Radius of Earth
This equation can be differentiated with respect to the radius of change, that is


At the same time since Newton's second law we know that:

Where,
m = mass
a =Acceleration
From the previous value given for acceleration we have to

Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:




But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:


Therefore there is a weight loss of 0.3N every kilometer.
Explanation:
a chip on your shoulder is an example
Answer:
57 N
Explanation:
Were are told that the force
of gravity on Tomas is 57 N.
And it acts at an inclined angle of 65°
Thus;
The vertical component of the velocity is; F_y = 57 sin 65
While the horizontal component is;
F_x = 57 cos 65
Thus;
F_y = 51.66 N
F_x = 24.09 N
The net force will be;
F_net = √((F_y)² + (F_x)²)
F_net = √(51.66² + 24.09²)
F_net = √3249.0837
F_net = 57 N
Answer: B
adding force will add accesion
Answer:

Explanation:
So, we are looking for an expression of the amount of water that has been drained from the tub. The expression is in terms of v that represent the number of gallons of water drained since the plug was pulled. Since we are interested in the pounds of water that has been drained from the tub we need to take into account that for every gallon of water drained, 8.345 pounds have left the tub. Therefore, the expression for the weight of water Q that has been drained from the tub in terms of v is simply :

Where v is the amount of gallons that has been drained from the tub.
Have a nice day. let me know if I can help with anything else