Which of the Jovian planets have rings?
2 answers:
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Answer:
a) fem = 5.709 V, b) t = 0.196 s, c) t = 0.589 s, d) T = 0.785 s
Explanation:
This is an exercise in Faraday's law
fem= - N
fem = - N
The magnetic field and the area are constant
fem = - N B A
fem = - N B A (-sin θ)
fem = N B (π d² / 4) sin θ w
fem= N B d² w sin θ
with this expression we can correspond the questions
a) the peak of the electromotive force
this hen the sine of the angle is 1
sin θ = 1
fem = 77 1.18 0.10² 8.0
fem = 5.709 V
b) as the system has a constant angular velocity, we can use the angular kinematics relations
θ = w₀ t
t = θ/w₀
Recall that the angles are in radians, so the angle for the maximum of the sine is
θ= π/2
t =
t = 0.196 s
c) for the electromotive force to be negative, the sine function of being
sin θ= -1
whereby
θ = 3π/ 2
t =
t = 0.589 s
d) This electromotive force has values that change sinusoidally with an angular velocity of
w = 8 rad / s
angular velocity and period are related
w = 2π / T
T = 2π / w
T = 2π / 8
T = 0.785 s
Answer:
Explanation:
I1 = 3 A right
I2 = 6.8 A left
Let the distance is r from both the wires on the same side.
The formula for the magnetic field is given by
As the direction of current in both the wires is opposite to each other
so the net magnetic field is
B = B2 - B1