1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
neonofarm [45]
3 years ago
15

Which ones are correct?

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

120 x 10^3

7 x 10^5

9 x 10^4

Step-by-step explanation:

 

You might be interested in
What is the answer to 2 5/3-2 3/2=
jek_recluse [69]
First, we can convert both of them to improper fractions.

We do that by multiplying the denominator to the whole number, adding it to the numerator, and keeping the denominator.

2 5/3 - 2 3/2

So we have:

11/3 - 7/2

Convert both of them to denominators of 6:

22/6 - 21/6

Subtract the numerators and keep the denominators:

1/6
3 0
3 years ago
Read 2 more answers
What is the answer to this?
ra1l [238]
The answer to your question is = 184
5 0
2 years ago
Read 2 more answers
PLEASE HELP!!
Natasha2012 [34]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
2(3 – 4a) + 5(a – 7)
PilotLPTM [1.2K]

Answer:

The answer is -(29+3a).

Step-by-step explanation:

=2(3-4a)+5(a-7)

= 6- 8a +5a -35

= 6-35-8a+5a

= -29-3a

= -(29+3a)

<em>Hope</em><em> </em><em>it helps</em><em>.</em><em>.</em>

6 0
3 years ago
Read 2 more answers
g A trial jury of 6 people is selected from 20 people: 8 women and 12 men. What is the probability that the jury will have an od
cricket20 [7]

Answer: P(odd) = 0.499

Step-by-step explanation:

Given:

Total number of people = 20

Number of men = 12

Number of women = 8

Number of jury to be selected = 6

For the jury to have an odd number of women. it must have either of the three.

1. 1 woman , 5 men

2. 3 women, 3 men

3. 5 women, 1 man

The total possible ways of selecting the 6 people jury is;

N = 20C6 = 20!/6!(20-6)!

N = 38760

The possible ways of selecting;

Case 1 : 1 woman, 5 men

N1 = 8C1 × 12C5

N1 = 8 × 792 = 6336

Case 2 : 3 women , 3 men

N2 = 8C3 × 12C3

N2 = 12320

Case 3 : 5 women, 1 man

N3 = 8C5 × 12C1

N3 = 672

P(Odd) = (N1+N2+N3)/N

P(odd) = (6336+12320+672)/38760

P(odd) = 19328/38760

P(odd) = 0.499

6 0
3 years ago
Other questions:
  • How many carbon monoxide molecules are in 0.75 moles of carbon monoxide?
    9·1 answer
  • What is the definition of numerical expression
    9·2 answers
  • How is the graph of y=^3√0.5x related to its parent function,y=^3√x ? A.It is horizontally stretched by a factor of 0.5 B. It is
    15·1 answer
  • Which is the graph of f(x) = (2)-x ?
    10·1 answer
  • What does PAMDAS satands for?
    11·2 answers
  • The first two steps in determining the solution set of the system of equations, y = x2 – 6x + 12 and y = 2x – 4, algebraically a
    9·2 answers
  • Find the vertex of f(x) = 12 - 41 +3
    12·1 answer
  • What 1✋1=2 <br><br><br> Plzzzzzzz
    9·1 answer
  • What is 2 3/7 X78.....???
    14·1 answer
  • Does anyone know how to do this?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!