-(-(-)(-)(-10x)) = -5

We need to cancel out the negatives, so we need to simplify this.

To make things a bit easier for you, we can begin by counting out how many negatives we have. After counting, you should have a negative number count of 5. However, one of the negatives is apart of (-10x) so we'll have 4 negatives and then an extra negative in with 10x.

Remember that "-" could also be looked at as "-1."

So, if we break this down into smaller parts and substitute "-" into "-1," then this'll look like this :

-1 × -1 × -1 × -1 × (-10x) = -5

Remember that a negative times a negative is always a positive.

So, since there are four negatives, then you just multiply it all together.

This results in 1 × (-10x) = -5

Simplify.

-10x = -5

Now, you simply divide both sides by -10.

-10x ÷ -10 = -5 ÷ -10

Simplify.

x = 1/2

~Hope I helped!~

6 0

3 years ago

What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5

swat32

Let $k:y=m_1x+b_1$ and $l:y=m_2x+b_2$

$l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}$

We have $y=-\dfrac{2}{3}x+5\to _1=-\dfrac{2}{3}$

Therefore

$m_2=-\dfrac{1}{-\frac{2}{3}}=\dfrac{3}{2}$

We have the equation of a line: $y=\dfrac{3}{2}x+b$ .

Put the coordinates of the point (8, 1) to the equation of a line:

$1=\dfrac{3}{2}(8)+b$

$1=(3)(4)+b$

$1=12+b$ <em>subtract 11 from both sides</em>

$-11=b\to b=-11$

Answer: $\boxed{y=\dfrac{3}{2}x-11}$

3 0

3 years ago

What is the distance between (–6, 2) and (–6, –15)

nekit [7.7K]

Answer:

Step-by-step explanation:

Since the X's are the same, the only distance we need to find is between the two y's

3 0

2 years ago

Negative divided by a negative is a

Papessa [141]

Answer:

Positive

Step-by-step explanation:

A negative number divided by a negative number equals a positive number. Two negatives make a positive, so a negative number divided by a negative number equals a positive number.

Example: -/- = +

-10/-5=2

Have a good day and stay safe!

3 0

3 years ago