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3 years ago

What could you do to find the amount to each person must pay? Explain.

Mathematics

1 answer:

Shtirlitz [24]3 years ago

5 0

Divide both sides by 5 since there are 5 friends, you would get 5x-23.

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Absolute value |-46|

Ivahew [28]

Answer: the absolut value is 46

Step-by-step explanation:

8 0

3 years ago

[PLEASE ANSWER ASAP] The entrance fee to a circus for a child is RM(3x-y). The entrance fee for an adult is RM2y more than the e

Vinil7 [7]

The total cost that will be paid by the family will be RM(15x - y).

<h3>How to calculate the cost?</h3>

The entrance fee to a circus for a child is RM(3x-y).

The entrance fee for an adult is RM(3x - y) + RM2y = 3x + y.

Therefore, the cost for 2 adults and three children will be:

= 2(3x + y) + 3(3x - y)

= 6x + 2y + 9x- 3y

= 15x - y

Learn more about cost on:

brainly.com/question/25109150

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1 year ago

Dogs in the GoodDog Obedience School win a blue ribbon for learning how to sit, a green ribbon for learning how to roll over, an

Elan Coil [88]

There are 17 dogs who have not learned any tricks.

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3 years ago

A data set consists of the following data points:

aleksley [76]

<span>(3,5),
(5,8),
(6,13)
------
(14,26)/3

then use the point slope form of a line to find equation of line

</span> $y-y_1=m(x-x_1)
\\y - \frac{26}{3} = 2.5(x- \frac{14}{3})
\\y - \frac{26}{3} = \frac{5}{2} (x- \frac{14}{3})
\\y - \frac{26}{3} = \frac{5}{2} x- \frac{5}{2}\times\frac{14}{3}
\\y - \frac{26}{3} = \frac{5}{2} x- \frac{35}{3}
\\6y-52=15x-70
\\15x-6y-18=0$
<span>
Find y-intercept for x = 0.

</span> $15x-6y-18=0
\\15\times0-6y-18=0
\\-6y=18
\\y=-3$ <span>

</span>

4 0

3 years ago

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

2 years ago