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Dvinal [7]
3 years ago
14

Which of the following correctly describes the location of subatomic particles within an atom?

Chemistry
2 answers:
In-s [12.5K]3 years ago
8 0
The sky is blue or red on or dead wait... who am I.??
KonstantinChe [14]3 years ago
6 0

Answer:

electrons are located outside of the atoms nucleus

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Titration Volume & Concentration
polet [3.4K]

Answer:

18,1 mL of a 0,304M HCl solution.

Explanation:

The neutralization reaction of Ba(OH)₂ with HCl is:

2 HCl + Ba(OH)₂ → BaCl₂ + 2 H₂O

The moles of 17,1 mL≡0,0171L of a 0,161M Ba(OH)₂ solution are:

0,0171L*\frac{0,161moles}{L} = 2,7531x10⁻³moles of Ba(OH)₂

By the neutralization reaction you can see that 2 moles of HCl reacts with 1 mole of Ba(OH)₂. For a complete reaction of 2,7531x10⁻³moles of Ba(OH)₂ you need:

2,7531x10^{-3}molBa(OH)_{2}*\frac{2molHCl}{1molBa(OH)_{2}} = 5,5062x10⁻³moles of HCl.

The volume of a 0,304M HCl solution for a complete neutralization is:

5,5062x10^{-3}molHCl*\frac{1L}{0,304mol} = 0,0181L≡18,1mL

I hope it helps!

4 0
3 years ago
How do we know what earth’s interior is like below the deepest drill holes ???
anzhelika [568]
From rocks and lava and earthquakes
4 0
3 years ago
The modern form of the periodic table results in the _____ ,which states that when elements are
stiv31 [10]

Answer:

The periodic law states “When elements are arranged in order of increasing atomic number, there is a periodic repetition of their chemical and physical properties

4 0
3 years ago
Which action would not help a person stay safe during a tornado? O A. Moving away from outside walls B. Going into a storm shelt
Andrew [12]

Answer:

Driving to get supplies

Explanation:

8 0
3 years ago
What is the molality of 49 grams of NaCl in 469 grams of H2O (water)
mina [271]

Answer : The molality of sodium chloride is, 1.79 m

Explanation :

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (sodium chloride) = 49 g

M_{solute} = Molar mass of solute (sodium chloride) = 58.5 g/mol

W_{solvent} = Mass of solvent (water) = 469 g

Now put all the given values in above equation, we get:

\text{Molality of }NaCl=\frac{49g\times 1000}{58.5g/mol\times 469kg}\\\\\text{Molality of }NaCl=1.79mol/kg=1.79m

Hence, the molality of sodium chloride is, 1.79 m

5 0
4 years ago
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