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Mazyrski [523]
3 years ago
15

How do you tell by the formula that an element on the periodic table is a metal

Chemistry
1 answer:
Dmitrij [34]3 years ago
7 0
The metalloids are on the right side of the periodic table B, Si, Ge, As, Sb, Te, and At. The nonmetals are also on the right side next to the metalloids, there should be a He at the top right of the periodic table and there should be one more nonmetal at the top left of the periodic table that is H. And from the metals they are all on the middle next to the metalloids, starting from Li, Be, Na, and Mg as so on all of those are metals.
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Question 1 (1 point)<br> ROOTS--What is NOT a root function in plants?
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Answer:

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Explanation:

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3 0
3 years ago
What type of solvent would be required to dissolve nonpolar compounds?
mina [271]
For example, ionic compounds, which are very polar, are often soluble in the polar solvent water. Nonpolar substances are likely to dissolve in nonpolar solvents. For example, nonpolar molecular substances are likely to dissolve in hexane, a common nonpolar solvent.
4 0
2 years ago
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What does Hess's law state can be done in order to be able to react solid magnesium with oxygen gas safely (that is, without exp
aleksley [76]

Answer:

C. The reaction can be broken down and performed in steps

Explanation:

Hess's Law of Constant Heat Summation states that irrespective of the number of steps followed in a reaction, the total enthalpy change for the reaction is the sum of all enthalpy changes corresponding to all the steps in the overall reaction. The implication of this law is that  the change of enthalpy in a chemical reaction is independent of the pathway between the initial and final states of the system.

To obtain MgO safely without exposing magnesium to flame, the reaction sequence shown in the image attached may be carried out. Since the enthalpy of the overall reaction is independent of the pathway between the initial and final states of the system, the sum of the enthalpy of each step yields the enthalpy of formation of MgO.

3 0
3 years ago
Write the lewis structure for mgi2. draw the lewis dot structure for mgi2. include all lone pairs of electrons.
viktelen [127]
Lewis Structure is drawn in following steps,

1) Calculate Number of Valence Electrons:
    
# of Valence electrons in Mg  =  2
# of Valence electrons in I      =  7
# of Valence electrons in I      =  7
                                               ---------
Total Valence electrons          =  16

2) Draw Mg as a central atom surround it by two atoms of Iodine.

3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.

Total Valence electrons           16
- Four electrons                    -   4
                                              ----------
                                                  12

4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.

The final lewis structure formed is as follow, 

4 0
3 years ago
Diamond is forever" is one of the most successful advertising slogans of all time. but is it true? for the reaction shown below,
Zielflug [23.3K]

The given reaction is

C _{(Diamond)}\rightarrow C_{(Graphite)}

An element can exist in 2 or more different forms which have totally different chemical and physical properties. They are known an allotropes.

Diamond and Graphite are allotropic forms of carbon. In the given reaction, diamond is changing to graphite and we have to find out the standard free energy of this reaction. This will help us to find out whether this reaction is spontaneous at 298 K or not.

The following data is needed for calculations which is taken from standard reference table.

H_{f}^{0}(diamond)= 1.895 kJ/mol

H_{f}^{0}(graphite)= 0

S^{0}(diamond)=2.337 J/mol-K

S^{0}(graphite)=5.740 J/mol-K

Step 1: Find ΔH⁰ rxn for the given reaction.

The formula to calculate ΔH⁰ rxn is given below.

\bigtriangleup H^{0}_{rxn}= H_{f}(product)- H_{f}( reactant)

We have graphite on product side and diamond on reactant side.

Therefore, \bigtriangleup H^{0}_{rxn}= H_{f}(graphite)- H_{f}(diamond)

Let us plug in the values given above.

\bigtriangleup H^{0}_{rxn}= 0 - 1.895 kJ/mol

\bigtriangleup H^{0}_{rxn}=  - 1.895 kJ/mol

ΔH⁰ rxn for the given reaction is -1.895 kJ/mol

Step 2 : Find ΔS⁰ rxn for the given reaction.

The formula to calculate ΔS⁰ rxn is

\bigtriangleup S^{0}_{rxn}= S^{0}(product)- S^{0}( reactant)

\bigtriangleup S^{0}_{rxn}= S^{0}(graphite)- S^{0}(diamond)

\bigtriangleup S^{0}_{rxn}= (5.740J/mol.K) - (2.337 J/mol.K)

\bigtriangleup S^{0}_{rxn}= 3.403 J/mol.K

Let us convert this to kJ.

\frac{3.403J}{mol.K}\times \frac{1 kJ}{1000J}= 3.403\times 10^{-3}kJ/mol.K

ΔS⁰ rxn for the given reaction is 3.403 x 10⁻³ kJ/mol.K

Step 3: Find standard free energy ΔG⁰ rxn.

ΔG⁰ rxn for the given reaction is calculated as

\bigtriangleup G^{0}_{rxn}= \bigtriangleup H^{0}_{rxn}- T\times \bigtriangleup S^{0}_{rxn}

We have T = 298 K. Let us plug in the calculated values of ΔH⁰ rxn and ΔS⁰ rxn.

\bigtriangleup G^{0}_{rxn}= - 1.895 kJ/mol - [(298K)\times 3.403\times 10^{-3}kJ/mol.K]

\bigtriangleup G^{0}_{rxn}= - 1.895 kJ/mol - [1.014 kJ/mol]

\bigtriangleup G^{0}_{rxn}= - 2.909 kJ/mol

The standard free energy change for the given reaction is -2.909 kJ/mol

The negative value of delta G⁰ suggests that the given reaction is spontaneous at room temperature. That means diamond will slowly convert to graphite. The speed of this reaction is extremely slow, but yet the reaction is taking place. So over a period of time diamond will become graphite.

Therefore "Diamond is forever" is not true as it is going to get converted to graphite.

7 0
3 years ago
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