Answer:
1.135 M.
Explanation:
- For the reaction: <em>2HI → H₂ + I₂,</em>
The reaction is a second order reaction of HI,so the rate law of the reaction is: Rate = k[HI]².
- To solve this problem, we can use the integral law of second-order reactions:
<em>1/[A] = kt + 1/[A₀],</em>
where, k is the reate constant of the reaction (k = 1.57 x 10⁻⁵ M⁻¹s⁻¹),
t is the time of the reaction (t = 8 hours x 60 x 60 = 28800 s),
[A₀] is the initial concentration of HI ([A₀] = ?? M).
[A] is the remaining concentration of HI after hours ([A₀] = 0.75 M).
∵ 1/[A] = kt + 1/[A₀],
∴ 1/[A₀] = 1/[A] - kt
∴ 1/[A₀] = [1/(0.75 M)] - (1.57 x 10⁻⁵ M⁻¹s⁻¹)(28800 s) = 1.333 M⁻¹ - 0.4522 M⁻¹ = 0.8808 M⁻¹.
∴ [A₀] = 1/(0.0.8808 M⁻¹) = 1.135 M.
<em>So, the concentration of HI 8 hours earlier = 1.135 M.</em>
The music of the Middle East uses the _________, which uses only selected notes and contains a melody scrap. Select one:<span>a. Fasil
</span>
b. Magam
c. Taksim
d. Sema
Answer:
Lone pairs and bonding pairs
Explanation:
The electron domain around the central atom includes
- All lone pairs on the central atom
- All bonding pairs between the central atom and the atoms directly attached to it
Double and triple bonds count as single domains.
Thus, the nitrite ion has three electron domains:
- A lone pair
- An N-O single bond
- An N-O double bond
Answer:
Pentane » Hexane » Hexanol
Explanation:
Pentane and Hexane are simple molecular structured with discrete molecules having weak vanderwaals forces of attraction. But Hexane has high molecular mass than pentane hence pentane has lower boiling point than Hexane.
Hexanol has hydrogen bonds between highly electronegative oxygen atom and the hydrogen atom which break on high heat energy application hence it has high boiling point.
According to Charle's Law,
V/T = constant
where
V = volume
T = absolute temperature.
The law holds when the pressure of an ideal gas is held constant while temperature changes.
V₁ = 2.33 L, initial volume
T₁ = 30°C = 30+273 K = 303 K, initial temperature
T₂ = 300°C = 300+273 K = 573 K, final temperature
The final volume, V₂, is given by
V₂/T₂ = V₁/T₁
V₂ = (573 K)*(2.33/303 L/K)
= 4.406 L
Answer: 4.41 L
