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Gennadij [26K]
3 years ago
14

How many protons does one oxygen atom contain

Chemistry
2 answers:
Murljashka [212]3 years ago
7 0
The answer is 8 to you question
eimsori [14]3 years ago
6 0

Answer:

8

Explanation:

Its official chemical symbol is O, and its atomic number is 8, which means that an oxygen atom has eight protons in its nucleus

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Express the frequency in inverse seconds. n=5-->n=1
Natalija [7]

The frequencies expressed in inverse seconds are 5 s⁻¹  and 1 s⁻¹.

<h3>What is frequency?</h3>

Frequency is the number of complete cycles in a second made by a wave.

F = 1/T

F = n/t

<h3>When n = 5</h3>

F = 5/s =  5 s⁻¹ = 5Hz

<h3>When n = 1</h3>

F = 1/s =  1 s⁻¹ = 1Hz

Learn more about frequency here: brainly.com/question/254161

#SPJ1

4 0
2 years ago
Why isn’t there anyone helping for chemistry I need this by literally tomorrow morning before 8:30 ;-;
Naily [24]

Answer:

Find it in the teacher desk by tomorrow 7:30

Explanation:

4 0
3 years ago
Read 2 more answers
B. The following reaction takes place in a basic solution. (7 points)
Natali5045456 [20]

<u>Answer:</u> The final equation has hydroxide ions which indicate that the reaction has occurred in a basic medium.

<u>Explanation:</u>

Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously.

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when the oxidation number of a species increases.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when the oxidation number of a species decreases.

The given redox reaction follows:

MnO_4^-(aq)+NO_2^-(aq)\rightarrow MnO_2(s)+NO_3^-(aq)

To balance the given redox reaction in basic medium, there are few steps to be followed:

  • Writing the given oxidation and reduction half-reactions for the given equation with the correct number of electrons

Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-

  • Multiply each half-reaction by the correct number in order to balance charges for the two half-reactions

Oxidation half-reaction: NO_2^-+2OH^-\rightarrow NO_3^-+H_2O+2e^-         ( × 3)

Reduction half-reaction: MnO_4^-+2H_2O+3e^-\rightarrow MnO_2+4OH^-             ( × 2)

The half-reactions now become:

Oxidation half-reaction: 3NO_2^-+6OH^-\rightarrow 3NO_3^-+3H_2O+6e^-

Reduction half-reaction: 2MnO_4^-+4H_2O+3e^-\rightarrow 2MnO_2+8OH^-

  • Add the equations and simplify to get a balanced equation

Overall redox reaction: 3NO_2^-+2MnO_4^-+H_2O\rightarrow 3NO_3^-+2MnO_2+2OH^-

As we can see that in the overall redox reaction, hydroxide ions are released in the solution. Thus, making it a basic solution

3 0
3 years ago
11. Which of the following statements describe anions? Select all that apply.
Sveta_85 [38]
The two first ones because it’s always the opposite
4 0
2 years ago
Cci(4) will be soluble in
Romashka-Z-Leto [24]
LIKE DISSOLVES LIKE. Since Ccl4 is non-polar, it'll be soluble in any non-polar solvent. Hope this helps you!
8 0
3 years ago
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