C3H8 + 5O2 -----> 3CO2 + 4H2O
This is propane burning in air or pure oxygen.
The volume of a substance is simply the ratio of mass and
density. Therefore:
volume = mass / density
Calculating for volume of Carbon Tetrachloride that the
student has to pour out:
volume = 55.0 g / (1.59 g / cm^3)
<span>volume = 34.60 cm^3</span>
Volume of Argon V1 = 5.0 L
Pressure of Argon P1 = 2 atm
Final temperature T2 = 30 C = 30 + 273 = 303 K
Volume at final temperature V2= 6 L
Pressure at final temperature P2 = 8 atm
We know that (P1 x V1) / T1 = (P2 x V2) / T2
(2 x 5)/ T1 = (8 x 6)/ 303 => T1 = (10 x 303) / 48
Initial Temperature T1 = 3030 / 48 = 63.12
Initial Temperature = -209. 8 C
A pH scale runs from 1 to 14 with 7 being neutral.
1-6 has base like properties
8-14 has avid line properties
since this solution has a pH scale of 4.... the solution is basic
