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3 years ago

What is the mass of 3.5 moles of helium gas?

Chemistry

2 answers:

xeze [42]3 years ago

4 0

Answer:

14.009.107‬

Explanation:

Moles to Grams helium

1 mole is equal to 1 moles Helium, or 4.002602 grams

4.002602 x 3= 12.007.806

4.002602 : 2 = 2.001.301

12.007.806+2.001.301= 14.009.107‬

andrew11 [14]3 years ago

3 0

Answer:

1 mole is equal to 1 moles Helium, or 4.002602 grams.

Explanation:

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Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

3 years ago

Calculate the average bond order for a p−o bond (such as the one shown in blue) in a phosphate ion. express your answer numerica

PtichkaEL [24]

Answer: 1/4 is the average bond order for a pâ’o bond (such as the one shown in blue) in a phosphate ion.

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3 years ago

Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r

MakcuM [25]

Answer:

CH2O

Explanation:

Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.

C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

6 0

3 years ago

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Describe how the air pressure on Earth affects the weather.

11111nata11111 [884]

Answer:

As the pressure decreases, the amount of oxygen available to breathe also decreases. Atmospheric pressure is an indicator of weather. When a low-pressure system moves into an area, it usually leads to cloudiness, wind, and precipitation. High-pressure systems usually lead to fair, calm weather.

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3 years ago

Label each carbon atom with the appropriate geometry. Bin 1 points to a carbon bonded to a double bonded carbon and single bonde

N76 [4]

Answer:

Bin 1 points to a carbon bonded to a double bonded carbon and single bonded to two hydrogens. --- trigonal planar, tetrahedral

Bin 2 points to a carbon double bonded to a carbon and single bonded to a carbon and one hydrogen.------- trigonal planar, tetrahedral

Bin 3 is a carbon single bonded to two carbons and single bonded to two hydrogens. ----- tetrahedral, tetrahedral

Bin 4 is the same as bin 3.--------tetrahedral, tetrahedral

Bin 5 is a carbon triple bonded to a carbon and single bonded to a carbon.---- linear, tetrahedral

Bin 6 is triple bonded to a carbon and single bonded to a hydrogen.---linear, tetrahedral

Explanation:

A single C-C or C-H bond is in a tetrahedral geometry, the carbon atom is bonded to four species with a bond angle of 109°.

A C=C bond is trigonal planar with a bond angle of 120°.

Lastly, a C≡C bond has a linear geometry with a bond angle of 180° between the atoms of the bond.

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3 years ago