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Rudiy27
3 years ago
10

What is the mass of 3.5 moles of helium gas?

Chemistry
2 answers:
xeze [42]3 years ago
4 0

Answer:

14.009.107‬

Explanation:

Moles to Grams helium

1 mole is equal to 1 moles Helium, or 4.002602 grams

4.002602 x 3=  12.007.806

4.002602 : 2 = 2.001.301

12.007.806+2.001.301= 14.009.107‬

andrew11 [14]3 years ago
3 0

Answer:

1 mole is equal to 1 moles Helium, or 4.002602 grams.

Explanation:

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Magnesium has an atomic mass of 24.3. there are two isotopes of magnesium - one contains 12 neutrons and the other contains 13 n
Juli2301 [7.4K]
So what we know:
-Atomic Mass = Protons + Neutrons
-Atomic Number is the number of protons

Magnesium's atomic number is 12, so the natural occurring isotope for magnesium is Mg-12 (12 protons and 12 neutrons). Added up we have an atomic mass of 24 amu. Which means if we added one neutron in Mg-13, our atomic mass would be 25 amu.

We can use the equation:
(amu of isotope 1)x + (amu of isotop 2)(x-1) = Average atomic mass
where isotope 1 is the fractional abundance we're solving for.

Plugged in it looks like this:
24x + 25(1-x) = 24.3

Now to solve for x:
24x + 25 - 25x = 24.3
   -x + 25 = 24.3
        -x = -.7
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3 0
3 years ago
The generic metal hydroxide M(OH)2 has Ksp = 8.05×10−12. (NOTE: In this particular problem, because of the magnitude of the Ksp
vodka [1.7K]

Answer:

a. in pure water Solubility (x) = 1.26 x 10⁻⁴M

b. in 0.202M M⁺² Solubility (x) = 9.963 x 10⁻¹²M

The large drop in solubility is consistent with the common ion effect.

Explanation:

a. Solubility in pure water

Given:       M(OH)₂ ⇄ M⁺² + 2OH⁻

            I       ---            0          0

           C      ---             x          2x

           E       ---            x           2x

Ksp = [M⁺²][OH⁻]² = (x)(2x)² = 4x³ => x = CubeRt(Ksp/4)

solubility in pure water = x = CubeRt(8.05 x 10⁻¹²/4) = 1.26 x 10⁻⁴M

b. Solubility in presence of 0.202M M⁺² as common ion.

Given:       M(OH)₂ ⇄       M⁺²      +     2OH⁻

            I       ---            0.202M              0

           C      ---                 +x                 +2x

           E       ---           0.202M + x         2x

                                   ≈ 0.202M

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=> x = (8.05 x 10⁻¹²)/(0.202)(4) = 9.963 x 10⁻¹²M

6 0
2 years ago
The reaction A + 2B + C -- &gt;D + 2E is first order in reactant A, first order in B, and second order in C. What is the rate la
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Do not get the order the reactants are confused with the coefficients in the chemical equation. (just because the reaction has 2B does not mean the rate law will have [B]².  As shown in this example since it is first order therefore being [B] in the rate law)

I hope this helps. Let me know if anything is unclear in the comments.
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