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olasank [31]
2 years ago
13

Write anode and cathode in Zn-Ag galvanic cell​

Chemistry
1 answer:
melomori [17]2 years ago
8 0

Explanation:

Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

By convention in standard cell notation, the anode is written on the left and the cathode is written on the right. So, in this cell: Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

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If the H+ concentration is 0.00001 M, what is the OH- concentration?
Ne4ueva [31]

Answer:

1.00x10^-9

Explanation:

3 0
2 years ago
A naturally occurring oil co-distills with water to produce an oil/water distillate that is 20% oil by weight. If the molecular
Gelneren [198K]

Answer:

Explanation:

Partial pressure of oil = mole fraction of oil x total pressure

mole fraction of oil = mole of oil / mole of water + mole of oil

= mole of oil = mass of oil / molecular weight of oil

= 20 / 100 = .2

mole of water = 80 / 18

= 4.444

mole fraction of oil =  .2 / .2 + 4.444

= .2 / 4.644

Partial pressure of oil = mole fraction of oil x total pressure

= (.2 / 4.644 ) x 760 mm

= 32.73 mm Hg .

3 0
3 years ago
Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical
sineoko [7]

Explanation:

A strip of solid palladium metal is put into a beaker of nicl2

Palladium (Pd) + Nickel Chloride (NiCl2)

To answer this question properly you must refer to the reactivity series.

The activity series is a chart of metals listed in order of declining relative reactivity. The top metals are more reactive than the metals on the bottom.

In this series, Nickel is higher than Palladium. This means that if a Palladium strip is placed into a solution of a Ni salt, then a reaction will not take place, nothing would happen.

Because Pd is lower than Ni in the reactivity series.

There is no reaction so no equation.

7 0
3 years ago
In a strong acid–strong base titration (both monoprotic), if 25.0 milliliters of the base is required to completely neutralize 2
taurus [48]
B)The concentration of the acid (C₁) is the same as that of the base (C₂).

V₁=V₂

n(acid)=C₁V₁
n(base)=C₂V₂

HX + YOH = YX + H₂O

n(acid)=n(base)

C₁V₁=C₂V₂

C₁=C₂
5 0
3 years ago
Read 2 more answers
Calculate the pH of a solution that has a [OH−] of 2.6 × 10^−6 M.
TiliK225 [7]

Answer:

A. 8.4

Explanation:

[OH⁻] = 2.6 × 10⁻⁶               Take the negative log of each side

-log[OH⁻] = pOH = 5.59     Apply the pH/pOH relation

pH + pOH = 14.00               Insert the value of pOH

pH + 5.59 = 14.00               Subtract 5.59 from each side

pH = 14.00 -5.59 = 8.41

7 0
2 years ago
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