Answer:
(chemical engineering) The transmission of fluids through a nonporous, polymeric barrier (membrane) by an adsorption-solution-diffusion-desorption sequence.
Explanation:
Answer:
The equilibrium pressure of HCl is 5.40 atm
Explanation:
Kc = [HCl]^2/[H2][Cl2]
Initial pressure of H2 = 3.46 atm and Cl2 = 3.46 atm
Let the equilibrium pressure of HCl be y
From the equation of reaction, mole ratio of H2 to HCl is 1:2, equilibrium pressure of H2 is (3.46 - 0.5y)
Also, from the y of reaction, mole ratio of Cl2 to HCl is 1:2, equilibrium pressure of Cl2 is (3.46 - 0.5y)
Kc = 50.1
50.1 = y^2/(3.46 -y)(3.46 - y)
50.1(11.9716 - 3.46y + 0.25y^2) = y^2
12.525y^2 - 173.346y + 599.77716 = y^2
11.525y^2 - 173.346y + 599.77716 = 0
y^2 - 15.04y + 52.04 = 0
The value of y is obtained using the quadratic formula
y = [15.04 - (sqrt (-15.04^2 - 4×1×52.04))] ÷ 2(1) = (15.04 - 4.25) ÷ 2 = 10.79 ÷ 2 = 5.40 atm (to 2 decimal places)
I’m pretty sure it’s either stormy it snowy :)
<span>this is a limiting reagent problem.
first, balance the equation
4Na+ O2 ---> 2Na2O
use both the mass of Na and mass of O2 to figure out how much possible Na2O you could make.
start with Na and go to grams of Na2O
55.3 gNa x (1molNa/23.0gNa) x (2 molNa2O/4 molNa) x (62.0gNa2O/1molNa2O) = 75.5 gNa2O
do the same with O2
64.3 gO2 x (1 molO2/32.0gO2) x (2 molNa2O/1 mol O2) x (62.0gNa2O/1molNa2O) = 249.2 g Na2O
now you must pick the least amount of Na2O for the one that you actually get in the reaction. This is because you have to have both reacts still present for a reaction to occur. So after the Na runs out when it makes 75.5 gNa2O with O2, the reaction stops.
So, the mass of sodium oxide is
75.5 g</span>
The answer is A
According to research I have done, pure solids and liquids are not included in the equilibrium constant expression. If the concentration of a reactant in aqueous solution is increased, the position of equilibrium will move in the direction which minimises the effect of this increase in concentration, by using the added component up, to decrese it's concentration again.
