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katrin [286]
3 years ago
6

Consider the reaction between hydrazine and hydrogen to produce ammonia, N2H4(g)+H2(g)→2NH3(g). Use enthalpies of formation and

bond enthalpies to estimate the enthalpy of the nitrogen-nitrogen bond in N2H4. Express your answer in kilojoules to 3 significant figures.
Chemistry
1 answer:
sammy [17]3 years ago
6 0

Answer:

The answer is explained below:

Explanation:

Given the chemical equation:

                   N2H4(g)+H2(g)→2NH3(g)

The standard enthalpy of formation is given by the following formula:

            ΔH^0 rxn = ∑ B reactants - ∑ product

       -187.78 kJ/mol = [( 1x B N-N) + (1 x B N-H ) + (1 x b H-H)] - [ 6 x B N-H]

       -187.78 kJ/mol = [( 1x B N-N)  +(4 x 391 kJ/mol) + (1 x 436  kJ/mol)] - [ 6x 391  kJ/mol ]

        -187.78 kJ/mol =  B N-N  + (1564 + 436 - 2346) kJ/mol

                                       B   = 158.22 kJ/mol

So, in this case the enthalpy of N-N bond is 158 kJ/mol

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How many grams are in 1.946 moles of nacl
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Answer:

113.8g

Explanation:

Statement of problem: mass of 1.946mole of NaCl

Given parameters:

Number of moles of NaCl = 1.946mole

Unknown: mass of NaCl

Solution

To find the mass of NaCl, we apply the concept of moles which expresses the relationship between number of moles and mass according to the equation below:

                        Number of moles = \frac{mass}{molar mass}

To find the molar mass of NaCl:

                         the atomic mass of Na = 23g

                                atomic mass of Cl = 35.5g

                Molar mass of NaCl = (23 + 35.5) = 58.5gmol⁻¹

Mass of NaCl = Number of moles x molar mass of NaCl

Mass of NaCl = 1.946 x 58.5 = 113.8g

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3 years ago
3. A 0.025L solution of HCl is neutralized by 0.018L of a 1.0 M NaOH solution. What is the concentration of the HCl solution?​
Nookie1986 [14]

The concentration of the HCl solution is 0.72 M.

<h3>How do we calculate the concentration?</h3>

Concentration of the required solution by the use of the known concentration solution will be determine by using the below equation as:

M₁V₁ = M₂V₂, where

  • M₁ & V₁ are the molarity and volume of the HCl solution.
  • M₂ & V₂ are the molarity and volume of the NaOH solution.

On putting values in the above equation, we get

M₁ = (1)(0.018) / (0.025) = 0.72 M

Hence required concentration of HCl is 0.72M.

To know kore about molarity, visit the below link:

brainly.com/question/24305514

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