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Verdich [7]
3 years ago
5

Geometry/Math question that I'm having issues with, see the attached image.

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

x=30

Step-by-step explanation:

Vertical angles formed by intersecting lines are always equal so the an equation can be formed:

4x+30=5x to solve start by subtracting 4x on both sides

30=x

You might be interested in
. Evaluate x2+ 2y÷ 2w+ 3zfor w= -2, x= -5, y= 8, and z= -3
DENIUS [597]
-23
2x+2y/2w+3z
2(-5)+2(8)/2(-2)+3(-3)
-10+16/-4-9
-14-9
-23
8 0
3 years ago
Drew's van is 200 centimeters tall. The height limit for a bridge is 3
horrorfan [7]

Answer:

1. 100cm

2. 300.1cm

3. 200cm

4. 400cm

5. 299.00cm

Step-by-step explanation:

300-200=100

300+0.01=301

300-100=200

300+100=400

300-0.01=299.99

4 0
3 years ago
Darryl deposits $1,500 into a savings account that has a simple interest rate of 2.7%. Lori deposits $1,400 into a savings accou
igor_vitrenko [27]
Darryl:
Answer:
A = $1,905.00

(I = A - P = $405.00)

Equation:
A = P(1 + rt)

Lori:

Answer:
A = $1,932.00

(I = A - P = $532.00)

Equation:
A = P(1 + rt)

Thus $532-$405= $127 more in Lori's account
3 0
3 years ago
Read 2 more answers
What is the measure of
wel
The picture is blurry
3 0
3 years ago
Read 2 more answers
A quadratic equation is shown below:
sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

3x^{2}-11x+10=0 has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

\frac{d}{dx}(3x^{2}-11x+10)=6x-11

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}

6 0
3 years ago
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