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Verdich [7]
3 years ago
5

Geometry/Math question that I'm having issues with, see the attached image.

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

x=30

Step-by-step explanation:

Vertical angles formed by intersecting lines are always equal so the an equation can be formed:

4x+30=5x to solve start by subtracting 4x on both sides

30=x

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Find the value of z.
san4es73 [151]

Answer:

Option D, 110

Step-by-step explanation:

first we find x

10x+20-80=2(2x+15)

or, x=15

now, 10x+20 = 170

so, z = 360-170-80 = 110

7 0
3 years ago
What is the area of the shape below?
mixas84 [53]
76 cm,



(4•10=40)+((10-4)•6)= 76 units
5 0
3 years ago
What is the mode of 31, 29, 33, 37, 43, 38, 33 and 40
slega [8]

Answer:

33

Step-by-step explanation:

The answer is 33 since it is the number that is most repeated.

That is was the mode is.

8 0
2 years ago
A liquid is found to have a volume of 50 mL (in a graduated cylinder). When placed on a balance, the liquid and graduated cylind
Lena [83]
1g/ml


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8 0
2 years ago
A kite 100 feet above the ground is being blown away from the person holding its string in a direction parallel to the ground at
VARVARA [1.3K]

Answer:

  5√3 ft/s

Step-by-step explanation:

Let h represent the horizontal distance of the kite from the person. Let s represent the string length. Then the Pythagorean theorem tells us ...

  s^2 = 100^2 + h^2

  2s·ds/dt = 0 + 2h·dh/dt

  ds/dt = (h/s)·dh/dt

So, we need to know the horizontal distance when s=200.

  200^2 = 100^2 + h^2

  40000 -10000 = h^2

  h = 100√3

Substituting known values into the equation for ds/dt, we have ...

  ds/dt = (100√3)/(200)(10 ft/s) = 5√3 ft/s

The string must be let out at 5√3 ft/s when it is already 200 ft long.

6 0
3 years ago
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