To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
Answer:
d=hf+5
Step-by-step explanation:
Step 1: Factor out variable d.
d(f+5)=h
Step 2: Divide both sides by f+5.
d(f+5)f+5=hf+5
d=hf+5
Area = length x width
24 = (n-3) x 2
24 = 2n -6
2n = 30
n = 15
Length is 15-3 =12, width is 2
24 = 12 x 2
The sum of the two prime numbers is 85. This is an odd number. According to the Rule, the sum of the even prime number and the odd prime number is called an odd number.
Hannah is 10 and 3/4 years old
Step-by-step explanation:
