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Vika [28.1K]
3 years ago
7

Please answer this question correctly please answer this question correctly

Mathematics
1 answer:
Yanka [14]3 years ago
8 0

Answer:

\frac{(8+2)^2}{2} = 50

10+5^2-3 * 2^2 = 23

Step-by-step explanation:

\frac{(8+2)^2}{2}

\frac{10^2}{2}

\frac{100}{2}

50

------------------------------

10+5^2-3 * 2^2

10+25-3 * 4

10+25-12

35-12

23

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1+1= 5 yet my teacher says it’s 2

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In the figure angle G measures 102° and angle B measures 30° what is the measurement of angle B
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30 degrees is what the answer is because it says it in the question
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Prove the following equation has no solutions.<br><br> 13t+6=12+13t
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Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3√5 , KE = 8, LM:KN = 3:5 Find: KM, LM, KN, Area of KLMN
lora16 [44]
Q1)Find KM
As ME is perpendicular to KN, ∠KEM is a right angle
Therefore ΔKEM is a right angled triangle 
KE is given and and ME is also given, we need to find KM
for this we can use Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides.
KM² = KE² + ME²
KM² = 8² + (3√5)²
       = 64 + 9x5
KM = √109
KM = 10.44

Q2)Find LM
It is said that ratio of LM:KN is 3:5
Therefore if we take the length of one unit as x
length of LM is 3x
and the length of KN is 5x
KN is greater than LM by 2 units 
If we take the figure ∠K and ∠N are equal. 
Since the angles on opposite sides of the bases are equal then this is called an isosceles trapezoid. So if we draw a line from L that cuts KN perpendicularly at D, ΔKEM and ΔLDN are congruent therefore KE = DN
since KN is greater than LM due to KE and DN , the extra 2 units of KN correspond to 16 units 
KN = LM + 2x 
2x = KE + DN
2x = 8+8
x = 8
LM = 3x = 3*8 = 24

Q3)Find KN 
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same height ME = LD perpendicular distance between the 2 parallel sides 
same right angle when the perpendicular lines cut KN
∠K = ∠N 
when 2 angles and one side of one triangle is equal to two angles and one side on another triangle then the 2 triangles are congruent according to AAS theorem (AAS). Therefore KE = DN 
the distance ED = LM
Therefore KN = KE + ED + DN
 since ED = LM = 24
and KE + DN = 16
KN = 16 + 24 = 40
another way is since KN = 5x and x = 8
KN = 5 * 8 = 40

Q4)Find area KLMN
Area of trapezium can be calculated using the following general equation 
Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)
where perpendicular height - ME
2 parallel sides are KN and LM
substituting values into the general equation
Area = 1/2 * ME * (KN+ LM) 
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         = 3 x 2.23 * 32
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3 years ago
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Help please if you can will give branliest
Yuliya22 [10]

Answer:

i’m thinking it might be 10?

Step-by-step explanation:

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